The answer comes to be 2158.53. You cannot have the fraction of the atom. The approximate answer will be too low to calculate. It will be too low to understand as well. The question should be 2.11 * 10 raised to 23 atoms.
To find the number of moles of xenon in 5.66 x 10²³ atoms, you can use Avogadro's number, which is approximately 6.022 x 10²³ atoms per mole. Divide the number of atoms by Avogadro's number: [ \text{Moles of xenon} = \frac{5.66 \times 10^{23} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 0.94 \text{ moles}. ] Thus, 5.66 x 10²³ atoms of xenon is approximately 0.94 moles.
This is equivalent to 1,4 moles.
5,82 x 1023 atoms of tungsten equal 0,966 moles.
9,003 x 1023 atoms of iron correspond to 1,495 moles.
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
5.66 X 1023 atoms of xenon (1 mole Xe/6.022 X 1023) = 0.940 moles of xenon ------------------------------
5.66 x 10^23 atoms of xenon is equal to 0.094 moles.
This is equivalent to 1,4 moles.
5,82 x 1023 atoms of tungsten equal 0,966 moles.
9,003 x 1023 atoms of iron correspond to 1,495 moles.
2.36 moles x 6.022*10^23 atoms/mole. Moles cancel and you are left with 1.42*10^24 xenon atoms.
0,25 moles F2
56 moles × (6.02 × 1023) = 3.37 × 1024 atoms
There are 19.2 moles of fluorine in 3.2 moles of xenon hexafluoride. Xenon hexafluoride has 6 fluorine atoms in each molecule, so you multiply the moles of xenon hexafluoride by 6 to find the moles of fluorine.
Atomic Mass of Na: 23.0 grams1.50 moles × (6.02 × 1023 atoms) = 9.03 × 1023atoms
6.02 X 1023 particles per mole X .75 moles = 4.52 X 1023 molecules.
The answer depends on the quantity of Xenon.