1 Mol
26,4 g iridium is equal to 0,137 mol.
To find the number of moles of iridium in 26.4 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iridium (Ir) is approximately 192.22 g/mol. Therefore, the calculation is 26.4 g / 192.22 g/mol, which equals about 0.137 moles of iridium.
16 grams of oxygen how many moles is 0,5 moles.
~58 If iridium has a density of 22.42 g/cm3, 1300 grams of iridium would displace 1300/22.42 grams of water (as water has a density of 1 g/cm3). The shape of the iridium is irrelevant.
120 grams of calcium contain 2,994 moles.
26,4 g iridium is equal to 0,137 mol.
2,635 ounces equates to 74,701 grams.
To find the number of moles of iridium in 26.4 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iridium (Ir) is approximately 192.22 g/mol. Therefore, the calculation is 26.4 g / 192.22 g/mol, which equals about 0.137 moles of iridium.
16 grams of oxygen how many moles is 0,5 moles.
~58 If iridium has a density of 22.42 g/cm3, 1300 grams of iridium would displace 1300/22.42 grams of water (as water has a density of 1 g/cm3). The shape of the iridium is irrelevant.
2635 miles into how many km
53 grams ÷ 18.01 grams/mole = 2.94 moles
180 grams of water is 10 moles of water.
222,6 grams of iodine is equivalent to 1,754 moles.
120 grams of calcium contain 2,994 moles.
1,8 grams of fluorine is equivalent to 0,0947 moles.
0.377 grams of Kr is equal to 0,0045 moles.