26,4 g iridium is equal to 0,137 mol.
To find the number of moles in 26.35 grams of iridium, you first need to determine the molar mass of iridium, which is approximately 192.22 g/mol. Then you can use the formula: moles = mass / molar mass. Substituting the values, moles = 26.35 g / 192.22 g/mol ≈ 0.137 moles of iridium.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
26,4 g iridium is equal to 0,137 mol.
To find the number of moles in 26.35 grams of iridium, you first need to determine the molar mass of iridium, which is approximately 192.22 g/mol. Then you can use the formula: moles = mass / molar mass. Substituting the values, moles = 26.35 g / 192.22 g/mol ≈ 0.137 moles of iridium.
The formula is: number of moles = g Be/9,012.
14,84 g magnesium are equivalent to 0,61 moles.
97,5 g of oxygen is equal to 5,416 moles.
978 g calcium contain 24,4 moles.
573,28 of g of AgCI is equivalent to 4 moles.
67,4 g HCl is equivalent to 1,85 moles.
29,0 g of calcium is equal to 0,723 moles.
27.4 g H2O x 1 mole/18 g = 1.52 moles
~58 If iridium has a density of 22.42 g/cm3, 1300 grams of iridium would displace 1300/22.42 grams of water (as water has a density of 1 g/cm3). The shape of the iridium is irrelevant.
156 g calcium is equivalent to 3,89 moles.