Balanced equation. C2H6O + 3O2 --> 2CO2 + 3H2O 0.274 moles C2H6O (2 moles CO2/1 mole C2H6O) = 0.548 moles carbon dioxide produced ============================
Fe ions =,Fe 2+andFe 3+Oxygen ions =,O 2-So, as you should see, Fe3O4, is an invalid species as the charge on the first iron ion would be 3 * 2+ = 6 +, and the charge on the second iron ion would be 3 * 3+ = 9+. This can not equal 4 * 2- = 8 -.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
To calculate the moles of O2 produced, first find the moles of CO2 using its molar mass, which is 44.01 g/mol. Then, use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, multiply the moles of CO2 by the mole ratio to get the moles of O2 produced.
To find the moles of cesium chlorate needed to produce 2.7 moles of oxygen gas, use the balanced chemical equation for the decomposition of cesium chlorate: 2CsClO3 -> 2CsCl + 3O2 From the equation, it shows that 2 moles of cesium chlorate produce 3 moles of oxygen gas. Therefore, you will need (2/3) * 2.7 = 1.8 moles of cesium chlorate to produce 2.7 moles of oxygen gas.
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.
The balanced reaction equation is 4Al + 3O2 -> 2Al2O3. Therefore, 3 moles of O2 reacts with 4 moles of Al to form 2 moles of Al2O3. Since 0.78 mol of O2 is reacted, the number of moles of Al2O3 formed can be calculated using the stoichiometry of the reaction.
5 moles RbNO3 (3 moles O2/2 moles RbNO3) = 7.5 moles oxygen gas produced
Balanced equation. C2H6O + 3O2 --> 2CO2 + 3H2O 0.274 moles C2H6O (2 moles CO2/1 mole C2H6O) = 0.548 moles carbon dioxide produced ============================
Fe ions =,Fe 2+andFe 3+Oxygen ions =,O 2-So, as you should see, Fe3O4, is an invalid species as the charge on the first iron ion would be 3 * 2+ = 6 +, and the charge on the second iron ion would be 3 * 3+ = 9+. This can not equal 4 * 2- = 8 -.
The balanced chemical equation for the decomposition of potassium chlorate (KClO3) into oxygen (O2) and potassium chloride (KCl) is 2KClO3 -> 2KCl + 3O2. This means that for every 2 moles of KClO3, 2 moles of KCl and 3 moles of O2 are produced.
First you need to find the balanced reaction:2S + 3O2 --> 2SO3So using the balanced reaction we see that for every 3 moles of oxygen consumed, 2 moles of sulfur trioxide are produced:1.2 moles O2 consumed * (2 moles SO3/3 moles O2) = 0.8 mole of SO3 produced
One mole of sulfur reacts with 1.5 moles of oxygen to produce one mole of sulfur trioxide. So, with two moles of sulfur and three moles of oxygen, the limiting reactant is sulfur. Therefore, two moles of sulfur will produce two moles of sulfur trioxide.
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
The balanced chemical equation for the reaction is 2SO2 + O2 -> 2SO3. This means that for every 1 mole of O2 consumed, 2 moles of SO3 are produced. Therefore, 1.32 moles of O2 would produce 2.64 moles of SO3.
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
The balanced chemical equation for the reaction between oxygen (O2) and hydrogen sulfide (H2S) is: 2H2S + 3O2 -> 2SO2 + 2H2O From the equation, it is a 3:2 ratio of O2 to H2S. Therefore, if 2.3 moles of H2S are present, (2.3 moles H2S) * (3 moles O2 / 2 moles H2S) = 3.45 moles of O2 are needed.