If you have 0.5 moles of K₂CO₃, then you simply have 0.5 moles of K₂CO₃. The quantity of moles is a direct measurement, so there are no additional calculations needed. Therefore, the answer is 0.5 moles of K₂CO₃.
0.0137 mol
K2CO3 + 2 benzoic acid -> 2 potassium benzoate + H2CO3
the formula of potassium carbonate is k2co3 because the valency of potassium (k1+) valency of carbonate is (co32-) interchange the valencies and don't put the signs then it will become (k2co3) so the formulae of potassium carbonate is k2co3
16 grams of oxygen how many moles is 0,5 moles.
moles of what?
0.0137 mol
First, calculate the number of moles of K2CO3 in 10.0 grams. Next, write and balance the chemical equation for the reaction between HCl and K2CO3. Use the stoichiometry of the balanced equation to determine the number of moles of HCl required to react with the moles of K2CO3. Finally, use the molarity of the HCl solution to calculate the volume needed.
There are 3 ions present in K2CO3: 2 K+ ions and 1 CO3^2- ion. To calculate the total number of ions in 30.0 mL of 0.600 M K2CO3 solution, first determine the number of moles of K2CO3 using the molarity and volume. Then, use the stoichiometry to find the number of ions produced per mole of K2CO3.
To calculate the mass of K2CO3 needed, first convert 200 mL to liters (0.2 L). Then, determine the moles of potassium ions needed using the concentration (0.150 M) and volume (0.2 L) of the solution. Since each formula unit of K2CO3 contains 2 moles of potassium ions, you can then calculate the mass of K2CO3 needed using its molar mass.
1,5 moles of potassium carbonate have 276,41 g.
To determine the volume of NiNO32 needed to react with 45 mL of K2CO3, you need to use the stoichiometry of the reaction. First, write and balance the chemical equation for the reaction. Then, use the molarity of K2CO3 to calculate the moles of K2CO3 present. Finally, use the balanced equation to find the volume of NiNO32 needed based on the stoichiometry of the reaction.
To prepare a 0.50 by volume (v/v) K2CO3 solution, you need 0.50 liters of K2CO3 per 100 mL of solution. For 150 mL, this means you need 0.75 mL of K2CO3. The density of K2CO3 is approximately 2.43 g/cm³. Therefore, the mass of K2CO3 needed is calculated as follows: 0.75 mL × 2.43 g/mL = 1.83 grams.
K2CO3 + 2 benzoic acid -> 2 potassium benzoate + H2CO3
K= 2 C= 1 O=3 K2CO3= 6 atoms
As indicated by the subscript on the atomic symbol for oxygen, there are 3 oxygen atoms.
Potassium Carbonate
The symbol equation for Potassium Carbonate is...K2CO3:)