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If you have 0.5 moles of K₂CO₃, then you simply have 0.5 moles of K₂CO₃. The quantity of moles is a direct measurement, so there are no additional calculations needed. Therefore, the answer is 0.5 moles of K₂CO₃.

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1mo ago

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How many moles of Cu2(CO3)3 can be made from 5.67 g K2CO3?

0.0137 mol


What volume of 6.0 M HCl is required to react with 10.0 grams of K2CO3?

First, calculate the number of moles of K2CO3 in 10.0 grams. Next, write and balance the chemical equation for the reaction between HCl and K2CO3. Use the stoichiometry of the balanced equation to determine the number of moles of HCl required to react with the moles of K2CO3. Finally, use the molarity of the HCl solution to calculate the volume needed.


How many ions are present in 30.0 mL of 0.600 M K2CO3 solution?

There are 3 ions present in K2CO3: 2 K+ ions and 1 CO3^2- ion. To calculate the total number of ions in 30.0 mL of 0.600 M K2CO3 solution, first determine the number of moles of K2CO3 using the molarity and volume. Then, use the stoichiometry to find the number of ions produced per mole of K2CO3.


What mass of K2CO3 is needed to prepare 200 mL of a solution having a potassium ion concentration of 0.150 M?

To calculate the mass of K2CO3 needed, first convert 200 mL to liters (0.2 L). Then, determine the moles of potassium ions needed using the concentration (0.150 M) and volume (0.2 L) of the solution. Since each formula unit of K2CO3 contains 2 moles of potassium ions, you can then calculate the mass of K2CO3 needed using its molar mass.


How many grams of potasium carbonate are in 1.5 moles of this substance?

1,5 moles of potassium carbonate have 276,41 g.


What volume of 0.55m nino32 will react with 45ml of 1.50m k2co3 to form nico3and kno3?

To determine the volume of NiNO32 needed to react with 45 mL of K2CO3, you need to use the stoichiometry of the reaction. First, write and balance the chemical equation for the reaction. Then, use the molarity of K2CO3 to calculate the moles of K2CO3 present. Finally, use the balanced equation to find the volume of NiNO32 needed based on the stoichiometry of the reaction.


How many grams of solid K2CO3 are needed to prepare 150. ml of 0.50 by volume K2CO3 solution?

To prepare a 0.50 by volume (v/v) K2CO3 solution, you need 0.50 liters of K2CO3 per 100 mL of solution. For 150 mL, this means you need 0.75 mL of K2CO3. The density of K2CO3 is approximately 2.43 g/cm³. Therefore, the mass of K2CO3 needed is calculated as follows: 0.75 mL × 2.43 g/mL = 1.83 grams.


What is equation for rxn of benzoic acid with K2CO3?

K2CO3 + 2 benzoic acid -> 2 potassium benzoate + H2CO3


How many atoms are present in the compound K2CO3?

K= 2 C= 1 O=3 K2CO3= 6 atoms


How many atoms of oxygen are there in potassium carbonate K2CO3?

As indicated by the subscript on the atomic symbol for oxygen, there are 3 oxygen atoms.


What is the common name of K2CO3?

Potassium Carbonate


Chemical symbol for potassium carbonate?

The symbol equation for Potassium Carbonate is...K2CO3:)