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What else can I help you with?
A mixture of gases contains 0.25 mol oxygen gas and 1.50 mol carbon dioxide gas at STP the mole fraction of oxygen gas in its mixture is?
The total moles of gas in the mixture is 0.25 + 1.50 = 1.75 mol. The mole fraction of oxygen gas is the moles of oxygen gas divided by the total moles, so 0.25 mol / 1.75 mol = 0.143. Therefore, the mole fraction of oxygen gas in the mixture is 0.143.
What quantity of reactants remains after ignition of a mixture that contains 2 moles of C2H6 mixed with 1.6 moles of O2?
Balanced equation first. 2C2H6 + 7O2 -> 4CO2 +6H2O I suspect C2H6 of limiting the reaction. 2 moles C2H6 (1.6 moles O2/2 moles C2H6) = 1.6 moles O2 left over and all of the C2H6 is consumed.
How many moles of air are there in a 3 L container at 1 am pressure and 293 K?
Air is a mixture.
For every gallon of petrol used how much water is produced from the exhaust?
Well in a stoichiometric mixture you get about 9 moles of water for the 60.5 moles of fuel-air mixture you need for a homogenous mixture so about 15% if you're talking moles. For mass you'd have to do it by R.A.M which I can't be bothered to do right now.
A mixture containing 9 mol of F2 and 4 mol of S is allowed to react. How many moles of F2 remain after 3 mol of S have reacted?
After 3 moles of S have reacted, 3 moles of F2 will also have reacted since the reaction ratio is 1:1 based on the balanced chemical equation. This leaves 6 moles of F2 remaining (9 moles initially - 3 moles reacted).
What is mole percent?
Mole percent, or molar percent of a substance is the ratio of the moles of a substance in a mixture to the moles of the mixture. It represents the number of moles of a substance in a mixture as a percentage of the the total number of moles in the mixture. Mole % = (mol substance in a mixture) / (mol mixture) * 100
How would an experiment differ from using 10 Moles to 5 moles?
you have a different variable
How can one determine the mole fraction of a substance in a mixture?
To determine the mole fraction of a substance in a mixture, you divide the moles of the substance by the total moles of all substances in the mixture. This gives you a ratio that represents the proportion of that substance in the mixture.
Equal volumes of 0.120molL potassium nitrate and 0.160molL ironiiinitrate are mixed together What is the concentration of nitrate ions in the mixture?
To find the concentration of nitrate ions in the mixture, we first calculate the moles of nitrate ions from each salt using the formula moles = concentration x volume. For potassium nitrate: 0.120 mol/L x volume = moles of nitrate ions. For iron (II) nitrate: 0.160 mol/L x volume = moles of nitrate ions. Add the moles of nitrate ions from both salts to get the total moles of nitrate ions in the mixture. Finally, divide the total moles of nitrate ions by the total volume of the mixture to get the concentration of nitrate ions in the mixture.
What is the unit of mole fraction?
Mole fraction is dimensionless. It's the amount of moles of species "A" divided by the total amount of moles in the mixture. So "mole A / mole total" equals "dimensionless". To add clarity in the use of mole fractions, one could add as "unit" mole A / mole "mixture".
What is morefraction?
I think you mean molefraction; this is equal to the number of moles of a species A divided by the total number of moles of all species (including A) in a mixture. Thus the sum of all the mole fractions in a mixture is equal to 1.
If a mixture of sand and salt weighing 74 grams is composed of 48 percent salt How many moles of salt are there?
To find the moles of salt in the mixture, we need to first determine the mass of salt present. Since the mixture is 48% salt, the mass of salt can be calculated as 74 grams * 0.48 = 35.52 grams. Next, we convert the mass of salt to moles using the molar mass of salt (NaCl), which is approximately 58.44 g/mol. Therefore, the number of moles of salt in the mixture is 35.52 grams / 58.44 g/mol ≈ 0.61 moles.
What is the mole fraction of H2S in a mixture of gases made up of 7.0 g of H2S 10.0 g of CH4 and 12.0 g of O2?
First, calculate the number of moles of each gas: 7.0 g H2S = 0.25 moles, 10.0 g CH4 = 0.28 moles, and 12.0 g O2 = 0.38 moles. Next, calculate the total moles of gas in the mixture: 0.25 + 0.28 + 0.38 = 0.91 moles. Finally, calculate the mole fraction of H2S: 0.25 moles H2S / 0.91 moles total = 0.275 or 27.5%.
What is the mole fraction of H2S in a mixture of gases made up of 7.0 g of H2S 10.0 g of CH4 and 12.0 g of O?
First calculate the moles of each gas using their molar masses (H2S = 34 g/mol, CH4 = 16 g/mol, O2 = 32 g/mol). Then find the total moles in the mixture. Lastly, divide the moles of H2S by the total moles to get the mole fraction of H2S in the mixture.
A mixture of gases contains 0.25 mol oxygen gas and 1.50 mol carbon dioxide gas at STP the mole fraction of oxygen gas in its mixture is?
The total moles of gas in the mixture is 0.25 + 1.50 = 1.75 mol. The mole fraction of oxygen gas is the moles of oxygen gas divided by the total moles, so 0.25 mol / 1.75 mol = 0.143. Therefore, the mole fraction of oxygen gas in the mixture is 0.143.
A mixture of 0.220 moles of CO 0.350 moles H2 and 0.640 moles He has a total pressure of 2.95 Atm what is the pressure of H2?
The total moles of gas in the mixture is 0.220 + 0.350 + 0.640 = 1.210 moles. To find the pressure of H2, we need to consider the mole fraction of H2, which is 0.350/1.210 = 0.289. So, the pressure of H2 is 0.289 * 2.95 Atm = 0.852 Atm.
- If the mass of 0.8 moles mixtures of NO and CH4 gases is 17 grams;I. The number of moles of NO is greater than the number of moles of CH4II. CH4 in the mix is 8 grams.III. NO in the mix is 0.3 mole?
I. False - Since both gases contribute to the total mass, the number of moles of NO does not necessarily need to be greater than the number of moles of CH4. II. True - If the total mixture mass is 17 grams and CH4 is 8 grams, then the remaining mass must be of NO. III. True - If the total moles of the mixture is 0.8, and CH4 is 0.5 moles (8g/16 g/mol), then the moles of NO would be the remaining 0.3 moles.
