answersLogoWhite

0

Al + 3AgNO3 ==> Al(NO3)3 + 3Ag
0.75 moles AgNO3 will produce 1/3 x 0.75 moles of Al(NO3)3 b/c of the mole ratio in the balanced eq.
1/3 x 0.75 = 0.25 moles Al(NO3)3 will be produced.

User Avatar

Wiki User

8y ago

What else can I help you with?

Related Questions

What are the products when these react AlCl3 and HNO3 and AgNO3?

When AlCl3 reacts with HNO3, the products are Al(NO3)3 and HCl. When AlCl3 reacts with AgNO3, the products are AgCl and Al(NO3)3.


What reacts with salt?

For example silver nitrate: NaCl + AgNO3 = NaNO3 + AgCl(s)


How many moles of AgCl will be produced from 83.0 g of AgNO3 assuming NaCl is available in excess?

The balanced chemical equation for this reaction is: AgNO3 + NaCl -> AgCl + NaNO3 From this equation, we can see that 1 mole of AgNO3 produces 1 mole of AgCl. Since the molar mass of AgNO3 is 169.87 g/mol, 83.0 g of AgNO3 is equivalent to 0.488 moles. Therefore, 0.488 moles of AgCl will be produced.


What is the equation of copper reacts with silver nitrates solution?

The reaction is:Cu + AgNO3 = Ag + CuNO3


4.02 grams of AgNO3 react with excess NaCl how many grams of silver nitrate are produced?

AgNo3(aq) + NaCl(aq) -------------->AgCl (ppt) + No3(-) + Na(+) no silver nitrates are produced it is all consumed. only silver chloride is produced and precipitate . free nitrate and free sodium ions are produced but do not react with each other 1 Mole AgNo3 ------->169.9 gm 1 Mole Nacl ------->58.4 gm 1 Mole AgCl ------->143.3 gm 4.02 gm AgNO3 = (4.02 / 169.9) = 0.02366 M AgCl produced = 0.02366 M = 3.39 gm


Why agno3 titration?

AgNO3 titration is commonly used to determine the concentration of chloride ions in a solution. Silver nitrate (AgNO3) reacts with chloride ions to form a white precipitate of silver chloride. The amount of AgNO3 required to completely precipitate all the chloride ions can be used to calculate the concentration of chloride in the solution.


What product reacts with sodium chloride?

The reaction is: NaCl + AgNO3 = NaNO3 + AgCl(s) Silver chloride is a white precipitate.


What is the equation when ammonia reacts with silver nitrate?

The equation for the reaction between ammonia and silver nitrate is: 2NH3 + AgNO3 → AgNH3 + NO3


What precipitate is formed with MgSO4 and AgNO3?

A white precipitate of silver sulfate (Ag2SO4) is formed when magnesium sulfate (MgSO4) reacts with silver nitrate (AgNO3) due to the insolubility of silver sulfate in water.


What is the symbol of a cation or ion that forms a precipitate with AgNO3 that doesn't dissolve in HNO3?

When AgNo3 reacts with iodide ions, the precipitate of AgI is formed.AgI is insoluble in HNO3. The symbol of the cation os, I-.


How many moles of Ag are produced when starting with 6.2 moles of AgNO3?

6,2 moles of silver


How much AgCl is produced when 4.22 grams of AgNO3 react with 7.73 grams of AlCl3?

3.56 g 3 AgNO3 + AlCl3 --> 3 AgCl + Al(NO3)3 AgCl3 is the limiting reagent (I checked), so: 4.22 g AgNO3 * (1 mol AgNO3/169.88 g AgNO3) * (3 mol AgNO3/3 mol AgCl3) * (143.32 mol AgCl3/1 mol AgCl3) =3.56 g AgCl3See the Related Questions to the left for more information about solving stoichiometry problems of this nature.