Al + 3AgNO3 ==> Al(NO3)3 + 3Ag
0.75 moles AgNO3 will produce 1/3 x 0.75 moles of Al(NO3)3 b/c of the mole ratio in the balanced eq.
1/3 x 0.75 = 0.25 moles Al(NO3)3 will be produced.
6,2 moles of silver
AgNO3 powder is white but a little grey solid.
Yes, when lithium carbonate (Li2CO3) reacts with silver nitrate (AgNO3) to form silver carbonate (Ag2CO3) and lithium nitrate (LiNO3), a white precipitate of silver carbonate will form due to the low solubility of silver carbonate in water.
Salt can react with water to form a solution of sodium and chloride ions. It can also react with some metals, like sodium and potassium, to form their respective salt compounds. In addition, salt can react with acids to form neutralization reactions, where the salt and water are produced.
The silver nitrate solution (AgNO3) provides the silver in silver chloride.
When AlCl3 reacts with HNO3, the products are Al(NO3)3 and HCl. When AlCl3 reacts with AgNO3, the products are AgCl and Al(NO3)3.
For example silver nitrate: NaCl + AgNO3 = NaNO3 + AgCl(s)
The balanced chemical equation for this reaction is: AgNO3 + NaCl -> AgCl + NaNO3 From this equation, we can see that 1 mole of AgNO3 produces 1 mole of AgCl. Since the molar mass of AgNO3 is 169.87 g/mol, 83.0 g of AgNO3 is equivalent to 0.488 moles. Therefore, 0.488 moles of AgCl will be produced.
The reaction is:Cu + AgNO3 = Ag + CuNO3
AgNo3(aq) + NaCl(aq) -------------->AgCl (ppt) + No3(-) + Na(+) no silver nitrates are produced it is all consumed. only silver chloride is produced and precipitate . free nitrate and free sodium ions are produced but do not react with each other 1 Mole AgNo3 ------->169.9 gm 1 Mole Nacl ------->58.4 gm 1 Mole AgCl ------->143.3 gm 4.02 gm AgNO3 = (4.02 / 169.9) = 0.02366 M AgCl produced = 0.02366 M = 3.39 gm
AgNO3 titration is commonly used to determine the concentration of chloride ions in a solution. Silver nitrate (AgNO3) reacts with chloride ions to form a white precipitate of silver chloride. The amount of AgNO3 required to completely precipitate all the chloride ions can be used to calculate the concentration of chloride in the solution.
The reaction is: NaCl + AgNO3 = NaNO3 + AgCl(s) Silver chloride is a white precipitate.
The equation for the reaction between ammonia and silver nitrate is: 2NH3 + AgNO3 → AgNH3 + NO3
A white precipitate of silver sulfate (Ag2SO4) is formed when magnesium sulfate (MgSO4) reacts with silver nitrate (AgNO3) due to the insolubility of silver sulfate in water.
When AgNo3 reacts with iodide ions, the precipitate of AgI is formed.AgI is insoluble in HNO3. The symbol of the cation os, I-.
6,2 moles of silver
3.56 g 3 AgNO3 + AlCl3 --> 3 AgCl + Al(NO3)3 AgCl3 is the limiting reagent (I checked), so: 4.22 g AgNO3 * (1 mol AgNO3/169.88 g AgNO3) * (3 mol AgNO3/3 mol AgCl3) * (143.32 mol AgCl3/1 mol AgCl3) =3.56 g AgCl3See the Related Questions to the left for more information about solving stoichiometry problems of this nature.