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If 1 cup is equal to 251.8 grams how many moles of Na2CO3 are used?
To determine how many moles of Na2CO3 are used, you need to know the molar mass of Na2CO3. It is 105.99 g/mol. Then, you can calculate the number of moles using the given mass: mass in grams / molar mass = moles of Na2CO3.
How many moles of washing soda are there in 5g?
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
What is the weight in grams of a 0.5 N Na2CO3 used in determining the concentration of unknown HCl solution?
A 0.5N Na2CO3 used in determining the concentration of an unknown HCl solution has a weight of 1.06 grams. To find the weight, you need to first find out how many moles there are by calculating molarity times volume.
What is the balanced equation of the reactants MnSO4 and Na2CO3?
The balanced equation for the reaction between MnSO4 and Na2CO3 is: MnSO4 + Na2CO3 -> MnCO3 + Na2SO4.
How many moles is 0.75g of Na2CO3?
The formula mass of sodium carbonate, Na2CO3 is 2(23.0) + 12.0 + 3(16.0) = 106.0Amount of Na2CO3 = mass of sample/molar mass = 0.75/106.0 = 0.00708mol There are 0.00708 moles of Na2CO3 in a 0.75g pure sample.
How many moles of ions are produced by the dissociation of 0.5 mol of Na2CO3?
When Na2CO3 dissociates, it produces 3 moles of ions: 2 moles of Na+ ions and 1 mole of CO3^2- ions. So, if you have 0.5 moles of Na2CO3, you would produce 1.5 moles of ions in total.
How many moles of Na2CO3 are there in 10.0 L of 2.0 M soluton?
Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
What is the number of moles in 8.42g Na2CO3?
It is 0.0794 moles.
If 1 cup is equal to 251.8 grams how many moles of Na2CO3 are used?
To determine how many moles of Na2CO3 are used, you need to know the molar mass of Na2CO3. It is 105.99 g/mol. Then, you can calculate the number of moles using the given mass: mass in grams / molar mass = moles of Na2CO3.
How many moles of washing soda are there in 5g?
Washing soda is sodium carbonate, Na2CO3. Using the atomic weights from the periodic table and the subscripts in the formula, the molar mass of Na2CO3 = 106g/mol. 5g Na2CO3 x (1mol Na2CO3/106g/mol) = 0.05mol Na2CO3
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
How many grams of NaOH are formed from reacting 120g sodium carbonate with excess calcium hydroxide?
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
Convert the mass of Na2CO3 to moles with the molecular weight of 105.989?
the answer to your question is 0.0004 g/mol.
How many grams are in 0.577 mol Na2CO3?
To convert moles to grams, you need to multiply the number of moles by the molar mass of the substance. The molar mass of Na2CO3 (sodium carbonate) is 105.99 g/mol. So, to find the grams in 0.577 mol of Na2CO3, you would calculate 0.577 mol * 105.99 g/mol = approximately 60.98 grams of Na2CO3.
How many moles of ions are produced when 2 mol of Na2CO3 dissociate?
Na2CO32 * 2 = 4 moles sodium.===========================
How many mL of 0.1010 M HCl will be needed to titrate 0.3151 grams of primary standard Na2CO3?
To determine the volume of HCl needed, first calculate the moles of Na2CO3 using its molar mass. Then use the balanced chemical equation to find the moles of HCl required to fully react with the moles of Na2CO3. Finally, use the concentration of the HCl solution to calculate the volume required using the formula: moles = molarity x volume (in liters).
