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50g/28g= 1.7857 moles

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Q: How many moles of N2 are in 50g of it?
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How many moles of H2are needed to react with 0.90moles N2?

I assume you mean this reaction. N2 + 3H2 --> 2NH3 0.90 moles N2 (3 moles H2/1 mole N2) = 2.7 moles hydrogen gas needed =====================


If 5.0 moles of NH3 are produce how many moles of N2 must have been used?

If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.


How many moles does 50g of NaCl represent?

50 g of NaCl represent 0,856 moles.


How many moles of N are there in 0.189 grams of N20?

The answer is 0,0043 moles of N2.


How do you find if you have 14.5 moles of N2 how many moles of H2 are theoretically needed to produce 22.5 moles of NH3 according to the reaction N2 plus 3H2 2NH3?

N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------


How many moles of N2 reacted if 0.40 mole NH3 is produced?

2 x 0.60 = 1.2 the reaction is N2 + 3H2 -> 2NH3 (1 mole of nitrogen N2 give 2 moles of NH3)


How many moles of N2 are produced by the decomposition of 1.20 mol of NaN3?

The number of atoms is 45,166.10e23.


How many moles of NH3 can be produced from the reaction of 75g of N2?

0,044 moles of NH3 can be produced.


How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?

The reaction of nitrogen with hydrogen to form ammonia is: N2 +3H2 = 2NH3 Therefore to make 10 moles of ammonia you need 5 moles N2 and 15 moles H2


Calculate the amount of ammonia produced from 50g of N in the equation N2+3H2=2NH3?

In the equation N2+3H2=2NH3, the amount of ammonia produced from 50g of N would be 16.667g.


How many moles of ammonia gas are produced by the reaction of 3 mole of nitrogen gas with excess hydrogen gas N2 H2 ---- NH3?

N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================


What mass of NH3 is produced when 1.20 mol of N2 react completely in the following equation N2 plus 3H2 2NH3?

N2 + 3H2 ==> 2NH3moles N2 = 1.20 molesmoles NH3 formed = 1.20 moles N2 x 2 moles NH3/1 moles N2 = 2.40 moles NH3mass NH3 = 2.40 moles x 17 g/mole = 40.8 g NH3