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To find the moles of Mercury (II) oxide (HgO) needed to produce 125 grams of oxygen (O2), we first calculate the moles of O2. The molar mass of O2 is approximately 32 g/mol, so 125 g of O2 corresponds to about 3.91 moles (125 g ÷ 32 g/mol). The decomposition of 2 moles of HgO produces 1 mole of O2, meaning we need 7.82 moles of HgO (3.91 moles O2 × 2) to produce that amount of oxygen. Thus, 7.82 moles of mercury (II) oxide are required.
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How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
When heated mercury oxide produces oxygen plus mercury what would be the combined mass of oxygen and mercury if 20g of mercury oxide were heated?
If 20g of mercury oxide were heated, the combined mass of oxygen and mercury would be 20 grams.
How many grams of chloral are needed to produce 10.5 g DDT?
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
How many grams of Hg must react to produce 3.75 moles of O?
To determine how many grams of mercury (Hg) are needed to produce 3.75 moles of oxygen (O₂), we first consider the balanced chemical reaction for the formation of oxygen from mercury(II) oxide (HgO): 2 HgO → 2 Hg + O₂. From this, we see that 2 moles of HgO produce 1 mole of O₂, which means 3.75 moles of O₂ require 7.5 moles of Hg. The molar mass of Hg is approximately 200.59 g/mol, so 7.5 moles of Hg would weigh about 1,504.43 grams (7.5 moles × 200.59 g/mol).
How many grams of hydrogen must be added to 800 grams of oxygen to produce 900 grams of water?
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.
How many grams of mercury II oxide are needed to produce 1.56 L of oxygen gas according to the following reaction at 25C and 1 ATM?
You would need 5.7 grams of mercury II oxide to produce 1.56 L of oxygen gas according to the following reaction at those conditions.
How many grams of oxygen will be required to produce 25 moles of sulfur dioxide how many grams of oxygen will be required to produce 25 moles of sulfur dioxide?
800 g oxygen are needed.
How many grams of oxygen are needed to react with 350 grams of iron to produce 500 grams of fe203?
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
How many grams of potassium chlorate will produce 112.5g of oxygen?
To calculate the amount of potassium chlorate needed to produce 112.5g of oxygen, you first need to determine the molar ratio between potassium chlorate and oxygen. Then, use this ratio to convert the grams of oxygen to grams of potassium chlorate using the molar masses of each compound.
How many grams of calcium oxide are needed to produce 36.0 g of hg?
To calculate the amount of calcium oxide needed to produce 36.0 g of mercury (Hg), we need to first determine the molar ratio between calcium oxide and mercury. The molar ratio can be determined from the balanced chemical equation of the reaction. Once the molar ratio is known, we can use it to find the amount of calcium oxide needed to produce 36.0 g of mercury.
If Lavoisier heated 100 grams of powdered mercuric oxide to produce 93 grams of liquid mercury how much oxygen would be released?
By mass conservation, since 100g of mercuric oxide yielded 93g of mercury, the remaining 7g is the mass of oxygen released during heating. So, 7g of oxygen would be released.
When 31 grams of phosphorous reacts with oxygen 71 grams of an oxide phosphorus is the product. What mass of oxygen is needed to produce 13 grams of this product?
To find the mass of oxygen needed to produce 13 grams of the oxide, we first find the molar ratio between P and O in the product. Then, use this ratio to calculate the mass of oxygen needed. Since 71g of the oxide contains 31g of phosphorus, we can calculate the mass of oxygen needed for 13g of the oxide by setting up a proportion.
When heated mercury oxide produces oxygen plus mercury what would be the combined mass of oxygen and mercury if 20g of mercury oxide were heated?
If 20g of mercury oxide were heated, the combined mass of oxygen and mercury would be 20 grams.
How many grams of chloral are needed to produce 10.5 g DDT?
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
How many grams of Hg must react to produce 3.75 moles of O?
To determine how many grams of mercury (Hg) are needed to produce 3.75 moles of oxygen (O₂), we first consider the balanced chemical reaction for the formation of oxygen from mercury(II) oxide (HgO): 2 HgO → 2 Hg + O₂. From this, we see that 2 moles of HgO produce 1 mole of O₂, which means 3.75 moles of O₂ require 7.5 moles of Hg. The molar mass of Hg is approximately 200.59 g/mol, so 7.5 moles of Hg would weigh about 1,504.43 grams (7.5 moles × 200.59 g/mol).
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
