In the ground state, only one of the elements listed has 1 unpaired electron: aluminum (Al). Boron (B) has 3 unpaired electrons, oxygen (O) has 2 unpaired electrons, and fluorine (F) has 1 unpaired electron but is already fully paired in its 2p orbital. Therefore, the total count of elements with 1 unpaired electron is two: Al and F.
Yttrium has an atomic number of 39, and its ground-state electron configuration is [Kr] 5s². In this configuration, all electrons are paired, resulting in zero unpaired electrons. Therefore, Yttrium has 0 unpaired electrons in its ground-state configuration.
Aluminum has 13 electrons. Use aufbau principle or periodic table to put these electrons into orbitals. 1s2 2s2 2p6 3s2 3p1 Because there is a lone electron in the p orbital that is not paired, aluminum in its ground state has 1 unpaired electron.
Stadium (St) is an element with the atomic number 51. It has a ground-state electron configuration of [Kr] 4d¹⁰ 5s² 5p³. In this configuration, the 5p subshell has three electrons, which are unpaired. Therefore, there are three unpaired electrons in stadium.
Arsenic is paramagnetic because the electron configuration is {Ar}4s^2,3d^10,4p^3. Due to the unpaired electron at the end (4p^*3*) the atom in ground state is paramagnetic. **OR Arsenic would be paramagnetic since the 4 p orbitals each contain one electron with parallel spin. These three unpaired electrons give arsenic its paramagnetic property.
Radium (Ra) has an atomic number of 88, which means it has 88 electrons. Its electron configuration is [Rn] 7s², indicating that the 7s subshell is fully filled with two electrons, leaving no unpaired electrons. Therefore, radium has zero unpaired electrons in its ground state.
Boron (B), Aluminum (Al), and Bromine (Br) each have 1 unpaired electron in the ground state. Oxygen (O) does not have any unpaired electrons in its ground state configuration.
Iodine has one unpaired electron in its ground state.
There are three unpaired electrons in an atom of cobalt in its ground state. This can be determined by the electron configuration of cobalt, which is [Ar] 4s2 3d7. The 3d orbital has 5 electrons, so there are 3 unpaired electrons.
In its ground state, rhenium (Re) has 1 unpaired electron.
Noble gases, like helium, neon, and argon, have no unpaired electrons in their ground state electron configuration. This means that all of their electrons are paired up in orbitals.
Exactly 0.
There are three unpaired electrons in the ground state of a scandium atom (Sc). This is because scandium has an atomic number of 21, with an electron configuration of [Ar] 3d^1 4s^2, where the 3d orbital has one unpaired electron.
thee are exactly 10 that is a difficult question but yes it is 10
The first-row transition metal with the most unpaired electrons is manganese (Mn). Its expected ground-state electron configuration is [Ar] 3d5 4s2, meaning it has 5 unpaired electrons in the 3d subshell.
Magnesium has five unpaired electrons and is therefor paramagnetic
There are 0 unpaired electrons which would make it diamagnetic
The element with three unpaired electrons in its p orbital is phosphorus. Its electron configuration is [Ne] 3s^2 3p^3, where the last three electrons occupy three separate p orbitals, each with one unpaired electron.