Iodine has an atomic number of 53, which means it has 53 electrons. The electron configuration of iodine is [Kr] 4d¹⁰ 5s² 5p⁵. In this configuration, the filled orbitals include the 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, and 5s orbitals, totaling 10 filled orbitals: 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 4d¹⁰, and 5s². The 5p orbital has 5 electrons but is not fully filled, so it does not contribute to the count of filled orbitals.
The d sublevel always contains 5 orbitals. Therefore the d sublevel can accommodate 10 electrons just the same as 3d and 4d orbitals. Each of the 5 separate d orbitals can only contain two electrons.
Each orbital contains maximum or 2 electrons. you could be either asking for this OR s orbital contains maximum of 2 electrons (has 1 orbitals) p orbital contains maximum of 6 electrons (has 3 orbitals) d orbital contains maximum of 10 electrons (has 5 orbitals)
A neutral Si atom has 3 valence electrons, which reside in the 3rd energy level valence shell. Therefore, there are 3 valence orbitals in a neutral Si atom.
Orbitals don't contain elements. The elements each have specific orbitals based on the number of electrons it has. All of the elements have at least one s orbital. Hydrogen being the simplest element has one electron in the 1s orbital. The s orbital can contain a maximum of 2 electrons.
Iodine has 7 electron-containing orbitals, corresponding to its 7 valence electrons in the p subshell. These orbitals can hold a maximum of 2 electrons each.
There are 27 electron containing orbitals in an atom of Iodine.
The second shell in an atom contains 4 orbitals and can hold up to 8 electrons.
Three degenerate orbitals are needed to contain six electrons with two of them unpaired. Each orbital can hold a maximum of two electrons with opposite spins, totaling six electrons in three orbitals with two unpaired.
Iodine has an atomic number of 53, which means it has 53 electrons. The electron configuration of iodine is [Kr] 4d¹⁰ 5s² 5p⁵. In this configuration, the filled orbitals include the 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, and 5s orbitals, totaling 10 filled orbitals: 1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 4d¹⁰, and 5s². The 5p orbital has 5 electrons but is not fully filled, so it does not contribute to the count of filled orbitals.
Three degenerate orbitals are needed to contain seven electrons with five of them being paired in o orbitals. These would consist of two orbitals with 2 electrons each and one orbital with 3 electrons.
Multiply the orbitals in that sublevel by 2. The s sublevel has one orbital and can contain 2 electrons. The p sublevel has three orbitals and can contain 6 electrons. The d sublevel has five orbitals and can contain 10 electrons. The f sublevel has seven orbitals and can contain 14 electrons.
Iodine has 7 valance electrons
Three degenerate orbitals are needed to contain seven electrons with five unpaired. Two electrons will occupy two of the degenerate orbitals, while the remaining five electrons, each with one electron, will occupy the third degenerate orbital.
7 valence electrons in iodine
The electrons in beryllium occupy a total of four orbitals. Beryllium has 4 electrons, which fill the 1s, 2s, and 2p orbitals.
Iodine has 7 valence electrons.