One molecule of AlCl3 will dissociate into 4 particles: 1 aluminum ion
The kind of particles in a non electrolyte are those that do NOT dissociate or ionize. So, one particle of a non electrolyte remains as 1 particle. If it were an electrolyte it would dissociate into more than 1 particle.
The scattering angles would have changed, but the qualitative results would also change: the reason Rutherford chose gold was because it is EXTREMELY malleable. One can stretch gold foil until it is only a few atoms thick in places, which is not possible with aluminum. If the foil were too thick, there would be no transmission of particles at all; the whole point was to demonstrate that most alpha particles passed through unchanged, but some of them scattered, which is only possible with a VERY thin foil.
Aluminium has 13 protons and electrons and 14 neutrons. For a picture see this link.
No. The aluminum can does not have magnetic properties.
The term "oxygen particles" is not well defined, since it might refer to either oxygen atoms or oxygen molecules. Chemists would never describe oxygen in terms of particles, they would be specific. Ozone is the O3 molecule, containing 3 oxygen atoms. If you had 9 oxygen atoms you could make three ozone molecules. But if you had 9 oxygen molecules, you could make 6 ozone molecules, since the oxygen molecule is O2 and contains two oxygen atoms.
The longest wavelength that can dissociate a molecule of HI is determined by the ionization energy of the molecule. For HI, which has an ionization energy of 10.09 eV, the corresponding longest wavelength would be about 123 nm.
The kind of particles in a non electrolyte are those that do NOT dissociate or ionize. So, one particle of a non electrolyte remains as 1 particle. If it were an electrolyte it would dissociate into more than 1 particle.
they are both green on the periodic table of elements.... the alpha particles would follow the sam pattern. when the aluminum has a greater charge the particles would have a strong bend.
There would be 4.38 moles of fluoride ions in 1.46 moles of aluminum fluoride, as the formula for aluminum fluoride is AlF3 with three fluoride ions per molecule of aluminum fluoride.
Alpha radiation can be stopped by a sheet of paper, beta by a sheet of aluminum foil gamma... several feet of lead. Positrons are 'anti-electrons' and so it would annihilate itself in contact with an electron from normal metal.
For an element, it would be an atom. For a molecular substance, it would be a molecule. If it is an ionic compound, it would be a formula unit.
The scattering angles would have changed, but the qualitative results would also change: the reason Rutherford chose gold was because it is EXTREMELY malleable. One can stretch gold foil until it is only a few atoms thick in places, which is not possible with aluminum. If the foil were too thick, there would be no transmission of particles at all; the whole point was to demonstrate that most alpha particles passed through unchanged, but some of them scattered, which is only possible with a VERY thin foil.
It does if you want to detect the beta radiation. Beta radiation, beta particles, can be stopped with a sheet of aluminum foil. An aluminum "absorber" would act as a shield to the Geiger-Müller (GM) detector and stop the beta radiation, which is really high energy electrons or possibly positrons. Placing a shield between the source of the beta radiation and the GM detector would block the radiation, thus shielding the detector from it. The detector would be "blind" to the radiation. Note that this would be effective if all you wanted to do was look at gamma rays. The gamma rays and the beta radiation would leave the source and head to the GM detector, the beta particles would be blocked by the aluminum, and only the gamma rays would make it to the GM tube to be counted. Links can be found below.
Aluminium has 13 protons and electrons and 14 neutrons. For a picture see this link.
Freezing point depression is more significant if a molecule dissociates. It is the molality of the solution of osmotically active particles and freezing/melting point constant (k) of the solvent that determine the magnitude of freezing point depression. In these experiments, we are usually measuring freezing point depression to determine molar mass of the unknown solute. The calculated molar mass would be would be lower than the actual mass of the intact molecule. If you have half as many intact particles, the intact molecular weight must be double to obtain the same formula ratio: MW = g / mol ... since mol actually less of the intact particle, MW must be more
You would run a magnet over both of them together and the iron would stick to the magnet but the aluminum would not stick to the magnet or other way around. love, Hannah age 12
Free moving charged particles are particles that have an electric charge and are not bound to a specific atom or molecule. Examples include electrons and protons which can move independently and carry an electric current in a conductor.