1.50553543e+30 ppm
6.02 ten to the power of 23
-- Take the number of percent. -- Multiply it by 10,000-- The answer is the number of parts per million. . 10 percent = 100,000 parts per million.
When 1 mole of C8H18 is burned, it forms 8 moles of CO2. Therefore, when 451 moles of C8H18 is burned, it will form 8 * 451 = 3608 moles of CO2.
Also 0,1 mole carbon dioxide.
1 mole CO2 has about 44 grams, so half a mole of CO2 equals 22 grams
6.02 ten to the power of 23
-- Take the number of percent. -- Multiply it by 10,000-- The answer is the number of parts per million. . 10 percent = 100,000 parts per million.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms.
For every million parts of air there are 400 ppm (parts per million) or 0.04% of CO2(carbon dioxide). This is serious increase from 280 ppm (parts per million) or 0.028% which was the level for thousands of years before the Industrial Revolution, 200 years ago.
1 mole of CO2 has 1 mole of carbon atoms and 2 moles of oxygen atoms. So, 0.000831 mole of CO2 will have 0.000831 mole of carbon atoms.
The concentration of CO2 in rainwater with a pH of 5.6 is approximately 10 parts per million (ppm).
When 1 mole of C8H18 is burned, it forms 8 moles of CO2. Therefore, when 451 moles of C8H18 is burned, it will form 8 * 451 = 3608 moles of CO2.
Also 0,1 mole carbon dioxide.
1 mole CO2 has about 44 grams, so half a mole of CO2 equals 22 grams
One mole of glucose requires six moles of CO2 to enter the Calvin cycle for its synthesis.
Use dimensional analysis to solve this problem. First calculate the molecular mass of CO2. This is found by (use a periodic table) adding 12.011g of C to (15.999g x2) grams of Oxygen. Once you do that, you find out that 44.009g are in 1 mole of CO2. Now, simply by looking at the equation of CO2, we can tell that 2 moles of oxygen atoms are in 1 mole of Co2 (look at the subscript for Oxygen). Now, your dimensional analysis should look like this: 254g CO2 x 1 mole CO2/44.009g CO2 x 2 mole Oxygen/1 mole CO2 The answer is 11.5 moles of Oxygen in 254g of CO2.
CO2 + 4H2 --> CH4 + 2H2O0.500 moles CO2 (1 mole CH4/1 mole CO2) = 0.500 moles CH40.500 moles CO2 (2 moles H2O/1 mole CO2) = 1.00 moles H2O-------------------------------------------------------------------------------------add= 1.50 moles total product====================