4.55 moles AgNO3 (1 mole Ag/1 mole NO3)(6.022 X 10^23/1 mole Ag)
= 2.74 X 10^24 atoms of silver
0.688 moles*6.02x1023=4.14x1023 Formula units
To convert grams to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of AgNO3 is approximately 169.87 g/mol. Therefore, to convert 22.6g of AgNO3 to moles, you would divide 22.6g by 169.87 g/mol to get approximately 0.133 moles of AgNO3.
AgNO3
According to the periodic table, silver (Ag) has an atomic mass of about 108 grams per mole. If you have 802 grams, set up a direct proportion where 108/1=802/x and solve for x. You get about 7.43 moles of silver.
The unit used to count the number of silver atoms in a spoon would be the mole. A mole is a unit representing a specific number of atoms (Avogadro's number), which allows for convenient measurement and comparison of the amount of substance at the atomic or molecular scale.
To calculate the number of moles, you divide the number of atoms by Avogadro's number (6.022 x 10^23). So for 1.8 x 10^25 atoms of silver, the number of moles would be 30 moles.
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
0.688 moles*6.02x1023=4.14x1023 Formula units
To convert grams to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of AgNO3 is approximately 169.87 g/mol. Therefore, to convert 22.6g of AgNO3 to moles, you would divide 22.6g by 169.87 g/mol to get approximately 0.133 moles of AgNO3.
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
A silver sample with the same mass as the Earth (5.972 × 10^24 kg) would contain about 1.96 × 10^50 atoms of silver. This amount of silver corresponds to approximately 3.25 × 10^25 moles.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.
To find the number of atoms in the sample, you would first calculate the number of moles of silver in 1 x 10^-8 g using the molar mass of silver (107.87 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
AgNO3
The chemical formula for silver nitrate is AgNO3. To write it, you would denote the symbol "Ag" for silver and "NO3" for the nitrate ion, with the charge balanced to reflect a neutral compound.
agno3
The balanced equation for the reaction is AgNO3 (aq) + NaCl (aq) -> AgCl (s) + NaNO3. The coefficient of each reactant is the implied 1 when no explicit coefficient is shown in the equation. Therefore the same number of moles of silver nitrate as of sodium chloride are required for the reaction.