How many total atoms are in 4Ca3(po4)2?

Answer 1

To find the total number of atoms in the compound (4 \text{Ca}_3(\text{PO}_4)_2), first determine the composition of one formula unit of (\text{Ca}_3(\text{PO}_4)_2). It contains 3 calcium (Ca) atoms, 2 phosphorus (P) atoms, and 8 oxygen (O) atoms (since (2 \times 4 = 8)). Therefore, one formula unit has (3 + 2 + 8 = 13) atoms. Multiplying by 4 gives (4 \times 13 = 52) total atoms in (4 \text{Ca}_3(\text{PO}_4)_2).