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To find the total ions in 347 g of CaCl₂, first calculate the number of moles of CaCl₂ using its molar mass, which is approximately 110.98 g/mol. Dividing 347 g by the molar mass gives about 3.13 moles of CaCl₂. Each formula unit of CaCl₂ dissociates into one calcium ion (Ca²⁺) and two chloride ions (Cl⁻), totaling three ions per formula unit. Therefore, the total number of ions is 3.13 moles × 3 ions/mole = approximately 9.39 moles of ions, or about 5.65 × 10²⁴ ions.

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2w ago

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How many ions are present in CaCl2?

Calcium chloride ions are Ca(2+) and 2 Cl-.


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When CaCl2 is dissolved in water, it forms three ions in total: one Ca2+ ion and two Cl- ions.


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CaCl2 would have the highest number density of ions since it dissociates into 3 ions: one Ca2+ ion and two Cl- ions. This results in a total of 3 ions in solution per formula unit of CaCl2.


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salt. It's made by the two ions, Ca2+ and 2Cl- .


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When CaCl2 dissociates in water, it forms three ions: one Ca2+ ion and two Cl- ions for each formula unit of CaCl2. Therefore, 0.50 mol of CaCl2 would yield 0.50 mol Ca2+ ions and 1.0 mol Cl- ions in solution, totaling 1.5 moles of ions.


What type of bonding is present in cacl2?

Ionic bonding is present in CaCl2. In this type of bonding, electrons are transferred from the calcium atom to the chlorine atoms, creating oppositely charged ions that are held together by electrostatic forces.


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How many chloride ions are in a sample of salt that contains one mole of CaCl2?

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In 1.5 moles of CaCl2, you would have 3 moles of ions or atoms of calcium and 3 moles of ions of chloride. Since CaCl2 dissociates into 1 calcium ion (Ca2+) and 2 chloride ions (2Cl-), this means you would have 3 moles of calcium ions and 6 moles of chloride ions in total.


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