26 because phosphorous has five valence electrons and flouride has seven times three.
The PF6⁻ ion consists of one phosphorus (P) atom and six fluorine (F) atoms. Phosphorus has 5 valence electrons, and each fluorine atom has 7 valence electrons, contributing a total of 42 electrons from the six fluorine atoms. Adding the 5 from phosphorus and accounting for the extra electron due to the negative charge, the total number of valence electrons in PF6⁻ is 48.
Phosphorous (P) actually has a total of 15 electrons, but the 3 electrons referred to in the question are VALENCE electrons, i.e. outermost electrons.
Phosphorus has to gain a total of 3 electrons to achieve a noble gas configuration. You can find this for any non-metal because the last digit of its group number is the number of valence electrons it has. For example Phosphorus has 5 and Sulfur has 6. In order to achieve a noble gas electron configuration, you must have 8 valence electrons, so phosphorus must gain 3.
using the crossover rule i am sure it is 4
Calcium has a total of two valence electrons.
There are 15 electrons total, with 5 valence (outer shell) electrons
No such thing as pi3, but if you mean PI3, then there are 5 valence electron in P, and each I has 7 valence electrons for a total of 5 + 7 + 7 + 7 = 26 valence electrons.
The PF6⁻ ion consists of one phosphorus (P) atom and six fluorine (F) atoms. Phosphorus has 5 valence electrons, and each fluorine atom has 7 valence electrons, contributing a total of 42 electrons from the six fluorine atoms. Adding the 5 from phosphorus and accounting for the extra electron due to the negative charge, the total number of valence electrons in PF6⁻ is 48.
A phosphorus ion (P3-) has 8 electrons in its outermost energy level. This is because phosphorus has 5 electrons in its outermost shell, and when it gains 3 electrons to become an ion, it will have 8 electrons in total in its outermost energy level.
This is a chemical element. You can find the how many electron in a single atom by using a Periodic Table.
There are 26 total valence electrons in the compound PCl3. Phosphorus contributes 5 valence electrons, while each chlorine atom contributes 7 electrons. This adds up to 5 + (3 x 7) = 26 valence electrons.
Phosphorous (P) actually has a total of 15 electrons, but the 3 electrons referred to in the question are VALENCE electrons, i.e. outermost electrons.
The electron structure of ammonia (NH3) consists of two electrons in the 1s orbital, two in the 2s orbital, and three in the 2p orbital for a total of five valence electrons. Boron trifluoride (BF3) contains three valence electrons in the 2s and 2p orbitals of the boron atom, and three bonding pairs from the fluorine atoms.
Phosphorous has a total of 15 electrons, and of those, 3 of them are valence shell, or bonding electrons. So, 12 electrons are core electrons, and are non-bonding.
Phosphorus has to gain a total of 3 electrons to achieve a noble gas configuration. You can find this for any non-metal because the last digit of its group number is the number of valence electrons it has. For example Phosphorus has 5 and Sulfur has 6. In order to achieve a noble gas electron configuration, you must have 8 valence electrons, so phosphorus must gain 3.
Phosphorus has 10 core electrons. It is in the 3rd period of the periodic table and has an atomic number of 15. The inner electron configuration for phosphorus is [Ne]3s^23p^3, where [Ne] represents the noble gas configuration of Neon.
The element is sulphur. It has 5 valence electrons and 16 neutrons.