using the crossover rule i am sure it is 4
To find the number of molecules of PF3, we need to convert 150.0 grams of PF3 to moles, then use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules. The molar mass of PF3 is approximately 87.97 g/mol. By dividing 150.0 g by the molar mass, we get the number of moles, which can be converted to molecules.
PF3 (phosphorus trifluoride) does not have resonance structures. It has a single Lewis structure where phosphorus is bonded to three fluorine atoms with single covalent bonds, and phosphorus has a lone pair of electrons. Since there are no multiple bonds or delocalized electrons in PF3, resonance is not applicable. The molecule is stable in its one structure without the need for resonance.
There are 8.44 x 10^23 atoms in 1.4 moles of PF3. This value is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles (1.4) and the number of atoms in one molecule of PF3 (4).
PCl3 has more polar bonds than PF3 because chlorine is more electronegative than fluorine, resulting in greater electron density towards chlorine in PCl3.
To determine the mass of F2 needed to produce 120 g of PF3, we first need to calculate the molar mass of PF3, which is approximately 88 g/mol (phosphorus = 31 g/mol, fluorine = 19 g/mol × 3). The balanced chemical reaction for producing PF3 from P and F2 is: P + 3F2 → PF3. Since the molar ratio of PF3 to F2 is 1:3, we need 3 moles of F2 for every mole of PF3 produced. Therefore, for 120 g of PF3, which is about 1.36 moles (120 g / 88 g/mol), we would require approximately 4.08 moles of F2, or about 164 g (4.08 moles × 38 g/mol for F2).
The formal charge of P is 0 and the formal charge of F is 0.
The oxidation number of phosphorus (P) in PF3 is +3. This is because fluorine (F) has an oxidation number of -1, and the overall molecule PF3 has a total charge of 0.
There are 1
To find the number of molecules of PF3, we need to convert 150.0 grams of PF3 to moles, then use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules. The molar mass of PF3 is approximately 87.97 g/mol. By dividing 150.0 g by the molar mass, we get the number of moles, which can be converted to molecules.
covalent bond
The Lewis structure of PF3 shows that the central phosphorus atom has one non-bonding electron pair and three bonding electron pairs. Phosphorus has five valence electrons, and in PF3, one is non-bonding while the other three are shared in bonds with the fluorine atoms.
The intermolecular forces in PF3 are primarily dipole-dipole forces. This is because PF3 is a polar molecule, with a net dipole moment due to the unequal sharing of electrons between the phosphorus and fluorine atoms. This results in the positive and negative ends of the molecule attracting each other.
In phosphorus trifluoride (PF3), the bond angle is approximately 97 degrees. This angle is slightly less than the ideal tetrahedral bond angle of 109.5 degrees due to the presence of a lone pair of electrons on the phosphorus atom, which repels the bonding pairs and causes a distortion in the molecular geometry. As a result, PF3 adopts a trigonal pyramidal shape.
There are 8.44 x 10^23 atoms in 1.4 moles of PF3. This value is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles (1.4) and the number of atoms in one molecule of PF3 (4).
The chemical formula for phosphorus trifluoride is PF3.
PF3 is a molecular compound. It consists of a covalent bond between phosphorus and fluorine atoms.
The phosphorus atom in PF3 is sp3 hybridized. It forms three sigma bonds with the three fluorine atoms using three of its four sp3 hybridized orbitals. The remaining sp3 hybrid orbital contains a lone pair of electrons on the phosphorus atom.