The PF6⁻ ion consists of one phosphorus (P) atom and six fluorine (F) atoms. Phosphorus has 5 valence electrons, and each fluorine atom has 7 valence electrons, contributing a total of 42 electrons from the six fluorine atoms. Adding the 5 from phosphorus and accounting for the extra electron due to the negative charge, the total number of valence electrons in PF6⁻ is 48.
There are 15 electrons in phosphorus, 45 electrons from five fluorine atoms, and they make 60 electrons altogether.
CFC-113, or trichlorofluoromethane (CCl3F), has a total of 26 valence electrons. The carbon atom contributes 4 valence electrons, each of the three chlorine atoms contributes 7 valence electrons (totaling 21), and the fluorine atom contributes 7 valence electrons. Thus, the total count is 4 (C) + 21 (3 Cl) + 7 (F) = 32 valence electrons.
In the compound Al₂O₃, there are two aluminum (Al) atoms and three oxygen (O) atoms. Aluminum has 3 valence electrons, so 2 Al atoms contribute a total of 6 valence electrons. Oxygen has 6 valence electrons, so 3 O atoms contribute 18 valence electrons. Therefore, the total number of valence electrons in Al₂O₃ is 6 + 18 = 24 valence electrons.
The valence electrons are involved in the chemical bonding of atoms in a molecule.
There are 7 valence electrons in an NF3 molecule. Nitrogen has 5 valence electrons and each fluorine atom contributes 1 valence electron, totaling 3 electrons for the 3 fluorine atoms.
Xenon pentafluoride (XeF5) has a total of 8 valence electrons. Xenon (Xe) contributes 8 valence electrons, while each fluorine (F) atom contributes 7 valence electrons. The 5 fluorine atoms in XeF5 contribute a total of 35 valence electrons.
A fluorine atom has 7 valance electrons. This can be identified by looking which group fluorine is located, which is group 7. However when the atoms get bigger this rule does not apply so easily.
The PF6⁻ ion consists of one phosphorus (P) atom and six fluorine (F) atoms. Phosphorus has 5 valence electrons, and each fluorine atom has 7 valence electrons, contributing a total of 42 electrons from the six fluorine atoms. Adding the 5 from phosphorus and accounting for the extra electron due to the negative charge, the total number of valence electrons in PF6⁻ is 48.
Two fluorine atoms are needed to form an ionic bond with calcium, as each fluorine atom will contribute one electron to satisfy calcium's two valence electrons.
There are 15 electrons in phosphorus, 45 electrons from five fluorine atoms, and they make 60 electrons altogether.
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In IF3, iodine (I) has 7 valence electrons and each fluorine (F) has 7 valence electrons. Thus, the central iodine atom in IF3 is surrounded by 21 electrons from the three fluorine atoms (7 electrons each).
I believe you are talking about fluorine. If you are, F needs one more electron to gain a full shell.If you go to WikiAnswers for this information, that is counterproductive, because there is a much better way to do it. Look at the periodic table. Groups IA through VIIIA tell you what you need to know. IA has one valence electron, IIA has two valence electrons etc. Fluorine is in group VIIA and therefore has seven valence electrons. All atoms want eight, and thus fluorine is in need of one more.
Fluorine has seven electrons. Fluorine will form covalent and ionic bonds. Ionic- If it combines with any metal Covalent- If it bonds with a non-metal
A fluorine atom has 7 valence electrons. Fluorine atoms are highly reactive and tend to form bonds by gaining one more electron to achieve a full outer shell of 8 electrons, resulting in a stable octet configuration. This usually occurs through the formation of covalent bonds with other atoms.