6 x 2 = 12. 4 are part of a double covalent bond; the other 8 form lone/nonbonding pairs.
In the compound Al₂O₃, there are two aluminum (Al) atoms and three oxygen (O) atoms. Aluminum has 3 valence electrons, so 2 Al atoms contribute a total of 6 valence electrons. Oxygen has 6 valence electrons, so 3 O atoms contribute 18 valence electrons. Therefore, the total number of valence electrons in Al₂O₃ is 6 + 18 = 24 valence electrons.
N2O5 has 24 valence electrons. Each nitrogen contributes 5 valence electrons, and each oxygen contributes 6 valence electrons.
Calcium oxide (CaO) consists of calcium (Ca) and oxygen (O). Calcium, a group 2 element, has 2 valence electrons, while oxygen, a group 16 element, has 6 valence electrons. Therefore, in total, CaO has 2 (from Ca) + 6 (from O) = 8 valence electrons.
Zinc has two valence electrons.
Aluminum has 3 valence electrons.
O - Oxygen has 6 valence electrons.
In the compound Al₂O₃, there are two aluminum (Al) atoms and three oxygen (O) atoms. Aluminum has 3 valence electrons, so 2 Al atoms contribute a total of 6 valence electrons. Oxygen has 6 valence electrons, so 3 O atoms contribute 18 valence electrons. Therefore, the total number of valence electrons in Al₂O₃ is 6 + 18 = 24 valence electrons.
Here are 16 valence electrons: 3 from H, 8 from O and 5 from P.
N2O5 has 24 valence electrons. Each nitrogen contributes 5 valence electrons, and each oxygen contributes 6 valence electrons.
Here are 16 valence electrons: 3 from H, 8 from O and 5 from P.
Oxygen (O) has 6 valence electrons and fluorine (F) has 7 valence electrons. In OF2, there are a total of 18 valence electrons (6 from oxygen and 2 x 7 from fluorine).
Calcium oxide (CaO) consists of calcium (Ca) and oxygen (O). Calcium, a group 2 element, has 2 valence electrons, while oxygen, a group 16 element, has 6 valence electrons. Therefore, in total, CaO has 2 (from Ca) + 6 (from O) = 8 valence electrons.
The number of valence electrons in N and O is five and six, respectively. The total number of valence electrons in N2O is 16.
Each H has 1. Each O has 6 and the S has 6. That's a total of 32 valence electrons.
To find the total number of valence electrons in Li2O, we add the valence electrons of lithium (1 valence electron each) to the valence electrons of oxygen (6 valence electrons). So, Li2O has 2 (from Li) + 6 (from O) = 8 valence electrons.
Indium has 3 valence electrons.
Aspirin, or acetylsalicylic acid, has a molecular formula of C9H8O4. To determine the number of valence electrons, we add the valence electrons from each atom: carbon (C) has 4 valence electrons, hydrogen (H) has 1, and oxygen (O) has 6. Therefore, the calculation is (9 C × 4) + (8 H × 1) + (4 O × 6) = 36 + 8 + 24 = 68 valence electrons in total.