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What is the molarity of a solution dissolve 0.31 grams of HNO3 in 300ml of water?
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
How many moles of HNO3 are required to react with 6 moles of Cu?
The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is: 3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O According to the equation, 8 moles of HNO3 are required to react with 3 moles of Cu. Therefore, to react with 6 moles of Cu, you would need 16 moles of HNO3.
What is the molarity of a solution prepared by dissolving 0.31g of HNO3 in 300ml of water?
To find the molarity, first calculate the number of moles of HNO3: 0.31g / 63g/mol (molar mass of HNO3) = 0.0049 mol Then, convert 300ml to liters: 300ml/1000 = 0.3 L Finally, molarity = moles/volume = 0.0049 mol / 0.3 L = 0.0163 M
What is the lab normality of hno3?
One equivalent proton per mole, so molarity is equal to normality.
What is the molarity of srno32 in a solution resulting from mixing 150.0 ml of 0.0200 m hno3 with 150.0 ml of 0.0100 m sroh2?
You get 300 mL of 0.0100 M Sr(NO3)2 solution
What volume in drops of 16M HNO3 is required to react with 0.0214grams of Cu metal?
To find the volume of 16M HNO3 required to react with 0.0214g of Cu metal, you need to calculate the moles of Cu. Then, using the balanced equation for the reaction between Cu and HNO3 (Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O), you can determine the moles of HNO3 needed. Finally, using the molarity of the HNO3 solution, you can calculate the volume in drops.
What happens when CaCO3 is added to HNO3?
When CaCO3 is added to HNO3, a chemical reaction occurs where CaCO3 reacts with HNO3 to produce Ca(NO3)2, CO2, and H2O. This reaction is a double displacement reaction where the calcium ions in CaCO3 switch places with the nitrate ions in HNO3.
What is the molarity of HNO3 if 20.0 ml of the solution is needed to exactly neutralize 10.0 ml of a 1.67 M NaOH solution?
First write down the BALANCED reaction eq'n. HNO3 + NaOH = NaNO3 + H2O Note the molar ratios are all 1:1 :: 1:1 Next calculate the moles of NaOH ml Mol(NaOH) = 1.67 moles dm(-3) X 10 ml / 1000 NB THe 1000 is required to convert ml to dm^(3) , and then cancel down Hence mol(NaOH) = 0.0167 By '1:1' equivalence above , we need 0.0167 moles(HNO3( Hence 0.0167 = [Molarity/conc'n] X 20 ml / 1000 Algebraically rearrange. molarity/conc'n = 0.0167 x 1000 / 20 molarity = 0.835 Mol dm^(-3) or = 0.835 M .
What is the molarity of a solution dissolve 0.31 grams of HNO3 in 300ml of water?
Molarity = moles of solute/Liters of solution ( get moles of HNO3 and 300 ml = 0.300 Liters ) 0.31 grams Nitric acid (1 mole HNO3/63.018 grams) = 0.004919 moles HNO3 Molarity = 0.004919 moles HNO3/0.300 Liters = 0.0164 M HNO3
How many moles of HNO3 are required to react with 6 moles of Cu?
The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is: 3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O According to the equation, 8 moles of HNO3 are required to react with 3 moles of Cu. Therefore, to react with 6 moles of Cu, you would need 16 moles of HNO3.
A 3.0-milliliter sample of hno3 solution is exactly neutralized by 6.0 milliliters of 0.50 m koh what is the molarity of the hno3 sample?
The moles of KOH can be calculated as (0.50 mol/L) x (6.0 mL). Since KOH is in a 1:1 ratio with HNO3 in the neutralization reaction, the moles of HNO3 are the same as KOH. So, the molarity of the HNO3 sample would be (moles of HNO3) / (3.0 mL).
What is the molarity of nitric acid?
The molarity of nitric acid, HNO3, can vary depending on the concentration of the solution. For example, a 1 M solution of nitric acid would contain 1 mole of HNO3 per liter of solution. It is important to know the concentration or volume of the solution to determine the molarity of nitric acid.
What is the molarity of a solution prepared by dissolving 0.31g of HNO3 in 300ml of water?
To find the molarity, first calculate the number of moles of HNO3: 0.31g / 63g/mol (molar mass of HNO3) = 0.0049 mol Then, convert 300ml to liters: 300ml/1000 = 0.3 L Finally, molarity = moles/volume = 0.0049 mol / 0.3 L = 0.0163 M
How many moles of the base are required to neutralize one mole of the acid for the reaction of HNO3 and KOH?
1 Mole. HNO3 + KOH = KNO3 + H2O Note the molar ratios are all 1:1 :: 1:1 So by equivalence 1 mole HNO3 is neutralised by 1 mole KOH. , to produce 1 mole water and 1 mole potassium nitrate.
What mass of limestone in kg would be required to completely neutralize a 15.4 billion-liter lake that is 1.9105 M in H2SO4 and 8.7106 M in HNO3?
To calculate the amount of limestone needed, first determine the moles of H2SO4 and HNO3 in the lake. Then, use the stoichiometry of the neutralization reaction between limestone (CaCO3) and the acids to calculate the moles of limestone required to neutralize the acids. Finally, convert the moles of limestone to kilograms using the molar mass of CaCO3.
What is the molarity of an naoh solution if 4.37ml is titrated by 11.1 ml of 0.0904 m hno3?
The balanced equation for the reaction is 1 mole of NaOH to 1 mole of HNO3. Using the titration data, you can calculate the moles of HNO3 used. From there, you can determine the moles of NaOH present in the 4.37 ml solution. Finally, dividing the moles of NaOH by the volume of the NaOH solution in liters will give you the molarity.
How many mL of 0.4040 M HNO3 would be needed to neutralize 55.00 mL of 0.1234 M potassium hydroxide?
To determine the volume of HNO3 required to neutralize KOH, you can use the concept of stoichiometry. The mole ratio between HNO3 and KOH is 1:1. Calculate the moles of KOH from its molarity and volume, then use the mole ratio to find the moles of HNO3 needed. Finally, convert the moles of HNO3 to volume using its molarity, which will give you the milliliters needed.
