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How many moles of oxygen are required to react with 5 moles of butane?
Assuming complete combustion of butane, you need 15 moles of oxygen to react with 5 moles of butane according to the balanced chemical equation: [ 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O ]
How many moles of nitrogen dioxide are needed to react with 5.0 moles of water?
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
How many gram of f2 are required to react with 3.50 moles of nh3?
The balanced chemical equation for the reaction between F2 and NH3 is: 3 F2 + 4 NH3 -> 6 HF + N2 From the equation, we can see that 3 moles of F2 react with 4 moles of NH3. To find the moles of F2 required to react with 3.50 moles of NH3, we can set up a proportion: 3 moles F2 / 4 moles NH3 = x moles F2 / 3.50 moles NH3 Solving for x, we find that 2.625 moles of F2 are required. To convert this to grams, we use the molar mass of F2 which is approximately 38.00 g/mol. 2.625 moles F2 x 38.00 g/mol = 99.75 grams of F2 required to react with 3.50 moles of NH3.
How many moles of Cu(NO3)2 are produced when 3 moles Cu react?
When 3 moles Cu react 3 moles of copper nitrate are obtained.
How many moles of oxygen would it take to react to 5 moles of hydrogen?
The nunber of moles of oxygen is 2,5.
How many moles of the base are required to neutralize one mole of the acid for the reaction of HNO3 and KOH?
For the reaction between HNO3 (acid) and KOH (base), it is a 1:1 molar ratio reaction. This means that 1 mole of HNO3 will react with 1 mole of KOH. So, 1 mole of KOH is required to neutralize 1 mole of HNO3 in this reaction.
How many mls of a 2.00m solution of nitric acid are neded to completely react with 15.0g of sodium hydroxide according to the chemical action of hno3 plus naoh nano3 plus h2o?
NaOH = 40 Mwt so 15/40 moles present. This requires 15/40 moles of HNO3 from the above equation. The HNO3 contains 2 moles in 1000 ml and so 1 mole in 500 ml and therefore 500 x 15/40 = 137.5 mls required
How many moles of hno3 are needed to prepare 5.0 of a 2.0 m solution of hno3?
10
How many atoms of zinc react with 1.49 g HNO3?
To find out how many atoms of zinc react with 1.49 g of HNO3, you would first need to balance the chemical equation for the reaction. Then, you can convert the mass of HNO3 to moles using its molar mass. Finally, use the coefficients in the balanced equation to determine the mole ratio between zinc and HNO3 to find the number of atoms of zinc involved in the reaction.
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
How many moles of HNO3 are present in 450 g of HNO3?
To determine the number of moles of HNO3 present in 450 g, we first need to calculate the molar mass of HNO3, which is approximately 63.01 g/mol. Next, we use the formula moles = mass/molar mass to find the number of moles. Therefore, 450 g of HNO3 is equal to 7.14 moles of HNO3.
How many mL of 0.4040 M HNO3 would be needed to neutralize 55.00 mL of 0.1234 M potassium hydroxide?
To determine the volume of HNO3 required to neutralize KOH, you can use the concept of stoichiometry. The mole ratio between HNO3 and KOH is 1:1. Calculate the moles of KOH from its molarity and volume, then use the mole ratio to find the moles of HNO3 needed. Finally, convert the moles of HNO3 to volume using its molarity, which will give you the milliliters needed.
How many moles of hno3 are present in 40.0 mL of a 1.80 M solution of nitric acid?
You can calculate the moles of HNO3 using the formula: moles = molarity x volume (in liters). First, convert 40.0 mL to liters (0.040 L). Then, plug in the values into the formula: moles = 1.80 M x 0.040 L = 0.072 moles of HNO3.
How many grams would be in four 4 moles of nitric acid HNO3?
The molar mass of nitric acid (HNO3) is 63.01 g/mol. To find the total grams in 4 moles, you would multiply the molar mass by the number of moles: 63.01 g/mol x 4 mol = 252.04 grams. So, there would be 252.04 grams in four moles of nitric acid (HNO3).
How many moles of sodium hydroxide are required to neutralize 20 mol of nitric acid?
The balanced chemical equation for the neutralization between sodium hydroxide (NaOH) and nitric acid (HNO3) is 1 mol of NaOH reacts with 1 mol of HNO3. Therefore, 20 moles of nitric acid would require 20 moles of sodium hydroxide to neutralize it.
How many moles of O2 are required to react with 23.5 moles of methanol?
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------
How many moles of lithium hydroxide are required to react with 20 mol of CO2?
The balanced chemical equation for the reaction of lithium hydroxide with carbon dioxide is 2 LiOH + CO2 -> Li2CO3 + H2O. The mole ratio of LiOH to CO2 is 2:1, meaning that 40 moles of LiOH are required to react with 20 moles of CO2.
