To determine the number of moles of HNO3 present in 450 g, we first need to calculate the molar mass of HNO3, which is approximately 63.01 g/mol. Next, we use the formula moles = mass/molar mass to find the number of moles. Therefore, 450 g of HNO3 is equal to 7.14 moles of HNO3.
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
Molarity = moles/litermoles = 9.33 g Na2S x 1 mole/78 g = 0.1196 molesliters = 450 ml x 1L/1000 ml = 0.45 Lmolarity = 0.1196 moles/0.45 L = 0.266 M = 0.27 M (2 sig figs)
450 milligrams = 0.450 gram
There are approximately 0.0159 ounces in 450 milligrams.
To find the number of moles of hydrogen gas, we first need to calculate the number of moles of chlorine gas using the ideal gas law formula (PV = nRT). Once we have the moles of chlorine gas, we can determine the moles of hydrogen gas needed for the reaction. In this case, the stoichiometry of the reaction states that 1 mole of chlorine gas reacts with 1 mole of hydrogen gas, so the required moles of hydrogen gas will be equal to the moles of chlorine gas.
450 moles of C2H4 contain 10.815,43 g carbon.
First, calculate the number of moles of NaOH: Moles = Molarity x Volume (L) Convert mL to L: 450 mL = 0.45 L Moles = 0.25 N x 0.45 L = 0.1125 moles of NaOH.
Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters) 5M C6H12O6 = moles C6H12O6/0.450 liters = 2.25 moles C6H12O6 (180.156 grams/1 mole C6H12O6) = 405.351 grams of glucose ( you do significant figures )
To calculate the number of molecules, first convert 450 g of water to moles (8 moles). With a 1.3 m solution, there are 1.3 moles of sucrose for every 1 liter of water. So, you will need 10.4 moles of sucrose for 8 moles of water. Finally, use Avogadro's number to convert moles to molecules, giving you approximately 6.23 x 10^23 molecules of sucrose.
I assume you mean 32.0 grams of NaOH and 450 milliliters of NaOH. Molarity = moles of solute/Liters of solution ( 450 ml = 0.450 liters ) get moles of NaOH 32.0 grams NaOH (1 mole NaOH/39.998 grams) = 0.800 moles NaOH Molarity = 0.800 moles NaOH/0.450 liters = 1.78 Molar NaOH
To find the number of moles in I2, we have to know the atomic weight of iodine (which my periodic table tells me is 127). But iodine is a diatomic element, existing in molecules of 2 iodine atoms bound together (I2). So the molecular weight of I2 is 2 x 127 = 254g/mole. Moles = mass/MW, so moles = 450g/(254g/mole). The "grams" cancel out and the answer is 1.77 moles.
450
There are 2.3888... 450 in 1075 1075 ÷ 450 = 2.3888...
45000 ÷ 100 = 450
The answer depends on 450 what. 450 hectolitres, 450 litres, 450 gallons or whatever will all give different answers.
450 prophets is the answer :)
Molarity = moles/litermoles = 9.33 g Na2S x 1 mole/78 g = 0.1196 molesliters = 450 ml x 1L/1000 ml = 0.45 Lmolarity = 0.1196 moles/0.45 L = 0.266 M = 0.27 M (2 sig figs)