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To find the number of moles in I2, we have to know the atomic weight of iodine (which my Periodic Table tells me is 127). But iodine is a diatomic element, existing in molecules of 2 iodine atoms bound together (I2). So the molecular weight of I2 is 2 x 127 = 254g/mole.

Moles = mass/MW, so moles = 450g/(254g/mole). The "grams" cancel out and the answer is 1.77 moles.

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Related Questions

What is the number of moles in 12.7 grams of iodine?

For this you need the atomic (molecular) mass of I2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. I2=253.8 grams12.7 grams I2 / (253.8 grams) = .0500 moles I2


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To prepare a 0.20 M solution of I2 in CCl4, you would need to calculate the moles of I2 required first. Molarity (M) = moles of solute / liters of solution. Since you know the molarity and volume of the solution, you can calculate the moles of I2 required and then convert that to grams using the molar mass of I2.


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From the balanced chemical equation, 2 moles of potassium iodide (KI) react with 1 mole of fluorine (F2) to produce 2 moles of iodine (I2). Therefore, when 0.72 mol of fluorine reacts, it produces 0.72 mol/2 = 0.36 mol of iodine. To convert this to grams, you would multiply the moles by the molar mass of iodine (I2), which is approximately 253.8 g/mol. So, 0.36 mol * 253.8 g/mol ≈ 91.4 grams of iodine are produced.


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not sure


What is the stoichiometric relationship between IO3- and I2?

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Equal weight of Zinc metal and Iodine are mixed together and the Iodine is completely converted to zinc iodide What fraction of weight of the original Zinc remains unreacted?

Balanced equation is: Zn(s) + I2(s) --> ZnI2(s) Pick any initial mass of Zn and I2, and convert those masses to moles: 100 g Zn / 63.4 g/mol = 1.58 moles 100 g I2 / 253.8 g/mol = 0.394 mol I2 Since these two react in a 1:1 ratio, you will have used 0.394 moles of Zn to react with the 0.394 moles of I2. That would leave 1.58 - 0.394 = 1.186 moles of Zn unreacted. So, the fraction of the original zinc remaining would be 1.186 / 1.58 = .75 by sonu gupta


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