To find the number of moles in I2, we have to know the atomic weight of iodine (which my Periodic Table tells me is 127). But iodine is a diatomic element, existing in molecules of 2 iodine atoms bound together (I2). So the molecular weight of I2 is 2 x 127 = 254g/mole.
Moles = mass/MW, so moles = 450g/(254g/mole). The "grams" cancel out and the answer is 1.77 moles.
find max.intensity using the formula I=I1+I2+(2I1I2)1/2 and for min.intensity,I=I1+I2-(2I1I2)1/2.
Depends on the voltage. R equals V2/P . Or the current: R equals P/I2 .
Add a sound intensity of I1 = 0.5 W/m² to a sound intensity of I2 = 1 W/m² to a total Intensity of Itotal = 1.5 W/m².
For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 * (r1/r2)²I2 = I1 * (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.
E = Voltage of the circuit I = Current in the circuit R = Resistance in the circuit Ohm's Law states that given two variables in an electric circuit, the third can be calculated: R=E/I I=E/R E=I*R Power in any circuit can be calculated by one of the following: P=E*I P=I2*R P=E2/R
For this you need the atomic (molecular) mass of I2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. I2=253.8 grams12.7 grams I2 / (253.8 grams) = .0500 moles I2
I2 + 2Cl2 .==> ICl + ICl3 molar mass of I2 = 127 molar mass of Cl2 = 70.9 moles of I2 used = 25.4/127 = 0.2 moles of I2 moles of Cl2 used = 14.2/70.9 = 0.2 moles of Cl2 Since the stoichiometry indicates that each mole of I2 reacts with 2 moles of Cl2 to give 1 mole each of ICl and ICl3, you should get 0.1 moles of each product. The reason you don't get 0.2 moles is because the amount of I2 is limiting, and you can see that 2 moles of Cl2 will use up 1 mole of I2, so 0.2 moles of Cl2 will use up 0.1 moles of I2. So 0.1 moles of product is all you can get under these conditions
To get moles given representative particles, simply divide by Avogadro's number: 1.80x1024/6.02x1023 = approx. 3 moles I2.
A theoretical yield is the amount of substance you calculate mathematically, as opposed to the actual yield, which is the amount of substance you find using a balance.To find the theoretical yield, you need a balanced equation. In this case,Zn + I2 -> ZnI2So, that was easy enough. The theoretical yield is limited by the reagent present in the smaller quantity by moles, not by mass. You must take the mass you have of zinc multiplied by zinc's molar mass to find the number of moles of zinc. You must take the mass you have of I2 and multiply by the molar mass of I2.The limiting reagent is the substance of fewer moles. Since these two reagents react in a 1:1 ratio, you just need to compare and see which you have less of. This will give you the number of moles you can make of ZnI2, theoretically -- the theoretical yield.
Balanced equation is: Zn(s) + I2(s) --> ZnI2(s) Pick any initial mass of Zn and I2, and convert those masses to moles: 100 g Zn / 63.4 g/mol = 1.58 moles 100 g I2 / 253.8 g/mol = 0.394 mol I2 Since these two react in a 1:1 ratio, you will have used 0.394 moles of Zn to react with the 0.394 moles of I2. That would leave 1.58 - 0.394 = 1.186 moles of Zn unreacted. So, the fraction of the original zinc remaining would be 1.186 / 1.58 = .75 by sonu gupta
You cannot produce any Iodine from chlorine, because chlorine (Cl2, gas) is an element, hence it does not contain any Iodine (I2, solid with purple vapor). However when 8.00 moles Cl2 react with excess (>16) moles potassium Iodide (KI) then also 8.00 moles of Iodine are produced, not FROM but BY MEANS OF chlorine. Cl2 + 2KI --> 2 KCl + I2
The balanced equation for the reaction between Iodine and Hydrogen is: H2 + I2 --> 2HI The ratio of I2 to HI is 1:2 Therefore 1 mole of Iodine can form a maximum of 2 moles of Hydrogen Iodide
Standardization of sodium thiosulfate uses potassium iodate with excess potassium iodide and acidified. Iodine is liberated and that is titrated with sodium thiosulfate. KIO3 + 5KI + 3H2SO4 -----> 3K2SO4 + 3H2O + 3 I2 I2 + 2Na2S2O3 -------> 2NaI + Na2S4O6 So 1 mole of KIO3 produces 3 moles of Iodine. 1 moles of iodine reacts with 2 moles of thiosulfate. So 6 moles of sodium thiosulfate react with 1 mole of potassium iodate KIO3.
180g I2
molarity = no. of moles of solute/liter of solution no. of moles of I2 = mass in grams/molar mass = 4.65/253.81 = 0.01832 mol M = 0.01832 mol/0.235 L = 0.0780 mol/L
This is a trick question because "I2" is the chemical symbol for MOLECULAR iodine (your question did not say melt Iodine, it said melt I2).Only gaseous iodine is composed of I2 molecules and as it is a gas it CAN NOT melt.
i think it will be (I2) aqueous / (I2) CHCi3