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To find the number of moles in I2, we have to know the atomic weight of iodine (which my Periodic Table tells me is 127). But iodine is a diatomic element, existing in molecules of 2 iodine atoms bound together (I2). So the molecular weight of I2 is 2 x 127 = 254g/mole.

Moles = mass/MW, so moles = 450g/(254g/mole). The "grams" cancel out and the answer is 1.77 moles.

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Q: Find the moles of I2 in 450 grams of I2?
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What is the number of moles in 12.7 grams of iodine?

For this you need the atomic (molecular) mass of I2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. I2=253.8 grams12.7 grams I2 / (253.8 grams) = .0500 moles I2


What are 25.4 g of iodine and 14.2 g of cl made to react completely to yield a mixture of icl and icl3 cal the no of moles of icl and icl3?

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A theoretical yield is the amount of substance you calculate mathematically, as opposed to the actual yield, which is the amount of substance you find using a balance.To find the theoretical yield, you need a balanced equation. In this case,Zn + I2 -> ZnI2So, that was easy enough. The theoretical yield is limited by the reagent present in the smaller quantity by moles, not by mass. You must take the mass you have of zinc multiplied by zinc's molar mass to find the number of moles of zinc. You must take the mass you have of I2 and multiply by the molar mass of I2.The limiting reagent is the substance of fewer moles. Since these two reagents react in a 1:1 ratio, you just need to compare and see which you have less of. This will give you the number of moles you can make of ZnI2, theoretically -- the theoretical yield.


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