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molarity = no. of moles of solute/liter of solution no. of moles of I2 = mass in grams/molar mass = 4.65/253.81 = 0.01832 mol M = 0.01832 mol/0.235 L = 0.0780 mol/L
For this you need the atomic (molecular) mass of I2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. I2=253.8 grams12.7 grams I2 / (253.8 grams) = .0500 moles I2
To find the mass of iodine containing the same number of atoms as 25.0 grams of chlorine, we can first calculate the number of moles of chlorine using its molar mass (Cl: 35.45 g/mol). Next, using the mole ratio of chlorine to iodine (1:1), we can determine the number of moles of iodine. Finally, we can convert the moles of iodine to grams using the molar mass of iodine (I: 126.90 g/mol) to find the mass of iodine.
From the balanced chemical equation, 2 moles of potassium iodide (KI) react with 1 mole of fluorine (F2) to produce 2 moles of iodine (I2). Therefore, when 0.72 mol of fluorine reacts, it produces 0.72 mol/2 = 0.36 mol of iodine. To convert this to grams, you would multiply the moles by the molar mass of iodine (I2), which is approximately 253.8 g/mol. So, 0.36 mol * 253.8 g/mol ≈ 91.4 grams of iodine are produced.
To calculate the number of moles of calcium in 425 g, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. moles = 425 g / 40.08 g/mol ≈ 10.61 moles of calcium.
To calculate the number of moles in 10g of iodine, you need to first determine the molar mass of iodine (I), which is 126.9 g/mol. Then, you can use the formula: moles = mass / molar mass. So, moles = 10g / 126.9 g/mol ≈ 0.079 moles of iodine.
mol = mass/Mr rearrange mol x Mr = mass 2 x 126.9g = 253.8g
To calculate moles use the eq'n moles = mass(g) / Mr (Relative molceular Mass). We have a mass of 135 g The Mr is calcualted from the Periodic Table, using atomic weights/masses. HBr = 1 x H = 1 x 1 = 1 1 x Br = 1 x 79.9 = 79.9 79.9 + 1 = 80.9 Substituting into the eq'n moles(HBr) = 135 / 80.9 Moles = 1.66872..... ~ 1.67 moles.
molarity = no. of moles of solute/liter of solution no. of moles of I2 = mass in grams/molar mass = 4.65/253.81 = 0.01832 mol M = 0.01832 mol/0.235 L = 0.0780 mol/L
For this you need the atomic (molecular) mass of I2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. I2=253.8 grams12.7 grams I2 / (253.8 grams) = .0500 moles I2
To find the mass of iodine containing the same number of atoms as 25.0 grams of chlorine, we can first calculate the number of moles of chlorine using its molar mass (Cl: 35.45 g/mol). Next, using the mole ratio of chlorine to iodine (1:1), we can determine the number of moles of iodine. Finally, we can convert the moles of iodine to grams using the molar mass of iodine (I: 126.90 g/mol) to find the mass of iodine.
1mole I atoms = 126.90447g1 mole I atoms = 6.022 x 1023 atoms IConvert grams I to moles I85.979g I x (1mol I/126.90447g I) = 0.67751mol IConvert moles I to atoms I0.6775mol I x (6.022 x 1023 atoms I/1mol I) = 4.080 x 1023 atoms I
.005078 g is the weight of 2 mole percent molecular iodine.
The formula is: number of moles = g Be/9,012.
From the balanced chemical equation, 2 moles of potassium iodide (KI) react with 1 mole of fluorine (F2) to produce 2 moles of iodine (I2). Therefore, when 0.72 mol of fluorine reacts, it produces 0.72 mol/2 = 0.36 mol of iodine. To convert this to grams, you would multiply the moles by the molar mass of iodine (I2), which is approximately 253.8 g/mol. So, 0.36 mol * 253.8 g/mol ≈ 91.4 grams of iodine are produced.
978 g calcium contain 24,4 moles.
29,0 g of calcium is equal to 0,723 moles.