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How many moles of H+ ions are present in the following aqueous solution? 1,410 mL of 0.32 M nitric acid
0.158 mol HNO3
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
20 moles of NaOH needed to neutralize 20 moles of nitric acid
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
How many moles of H+ ions are present in the following aqueous solution? 1,410 mL of 0.32 M nitric acid
0.158 mol HNO3
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
20 moles of NaOH needed to neutralize 20 moles of nitric acid
No. Nitric acid is only present in trace amounts in the atmosphere.
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
get the moles of hydrogen ions present in the solution by writing down the acid dissociation formula of the acid. Find the concentration of hydrogen ions present in the solution. Use -log[H+] to get the pH.
4 moles HNO3 (63.018 grams/1 mole HNO3) = 252 grams nitric acid ================
Two steps. Find molarity of nitric acid and need moles HNO3.Then find pH. 1.32 grams HNO3 (1 mole HNO3/63.018 grams) = 0.020946 moles nitric acid ------------------------------------- Molarity = moles of solute/Liters of solution ( 750 milliliters = 0.750 Liters ) Molarity = 0.020946 moles HNO3/0.750 Liters = 0.027928 M HNO3 ----------------------------------finally, - log(0.027928 M HNO3) = 1.55 pH ==========( could call it 1.6 pH )
The diluted solution has a slight hint of red as the other is just clear
by leaching the solution with nitric acid
Nitric Acid cannot react with Gold alone. The only solution that can dissolve Gold is Aqua Regia; a combination of Nitric Acid and Hydrochloric Acid.