To calculate the amount of NaNO3 needed to prepare a specific volume (in mL) of a molarity (M) solution, you can use the formula:
[ \text{mass (g)} = \text{molarity (M)} \times \text{volume (L)} \times \text{molar mass (g/mol)} ]
First, convert the volume from mL to L by dividing by 1000. Then, multiply the molarity by the volume in liters and the molar mass of NaNO3 (which is approximately 85 g/mol) to find the required mass in grams.
To calculate the amount of water needed, first determine the mass of formaldehyde in the final solution. Since the solution is 40.0% formaldehyde by mass, the mass of formaldehyde is 40.0% of the final solution mass. Subtract the mass of formaldehyde in 425 g from this value to find the mass of water needed to prepare the solution.
To prepare a 0.05 M disodium EDTA solution, you would need to dissolve 3.72 grams of disodium EDTA dihydrate (Na2C10H14N2Na2·2H2O) in enough water to make 1 liter of solution.
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To prepare a 0.5 M solution of disodium EDTA, you would need to calculate the molar mass of disodium EDTA (approximately 372.24 g/mol) and then use the formula: (given concentration x volume in liters) / molar mass = mass needed. So, for 0.5 M solution: (0.5 mol/L x 1 L) / 372.24 g/mol = 0.00134 kg or 1.34 g of disodium EDTA is needed.
You need 252 g sulfuric acid.
To prepare a 40.0% lithium nitrate solution, 60mL of the solution would be solvent (water) and 90mL would be solute (lithium nitrate). Therefore, you would need 90mL of lithium nitrate to prepare 150mL of the 40.0% solution.
To prepare a solution with a pH of 10.00, you will need to calculate the concentration of hydroxide ions. Once you have this concentration, you can determine the amount of NaOH needed to achieve this pH in 546 mL of solution.
Image result for You prepare a less concentrated H C l solution from a stock solution with 12m concentration. If you too 100g of the stock solution to prepare 4 MHCl solution how much water is needed to prepare o find solution 9density HCL(12) = 1,89/ml? The concentration would be 0.76 mol/L.
To calculate the amount of water needed, first determine the mass of formaldehyde in the final solution. Since the solution is 40.0% formaldehyde by mass, the mass of formaldehyde is 40.0% of the final solution mass. Subtract the mass of formaldehyde in 425 g from this value to find the mass of water needed to prepare the solution.
look on the box
RMM of CuSo4 . 5H2O = 160 + 5x18 = 250 g How much contain gram in 100 mL of 0.050 M CuSO4 solution is - Solution: = 0.050 x 100/1000 x 250 = 0.050x4 (100)/ 16 = 1.25 g
2.5ml
To prepare a 0.05 M disodium EDTA solution, you would need to dissolve 3.72 grams of disodium EDTA dihydrate (Na2C10H14N2Na2·2H2O) in enough water to make 1 liter of solution.
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To prepare 50 ml of a 1.0 M NaHCO3 solution from a 2.5 M stock solution, she would need to mix 10 ml of the 2.5 M solution with 40 ml of water. This dilution would result in a final concentration of 1.0 M.
To prepare a 500mM KCl solution, you would need to dissolve 74.55 grams of KCl in enough solvent to make 1 liter of solution.
50liters