First we convert horsepower to watts. 1 Horsepower equals 745.7 watts. Next, using the Ohm's law formula P=IxE where P is power measured in watts; I is current measured in amps; E is voltage measured in volts.
Therefore
5(745.7) / 240 = 15.5 amps
<<>> The current taken by a motor is highly variable depending on efficiency, power factor and the mechanical load. On a 240 v system you should allow 7 amps per HP. So for 5 HP you should allow 35 amps.
Since 2-phase systems went out of use 100 years ago you probably have a single-phase motor which has two suppy wires, a live and a neutral, plus probably an earth wire.
To calculate the current per phase, use the formula: Current (I) = Power (P) / (Square Root(3) x Voltage (V)). For an 18kW motor at 415V, the current per phase will be: 18,000W / (1.732 x 415V) ≈ 24.5A per phase.
P=VI P=power V=voltage I=current therefore current drawn is 5000/400=50/4=12.5 amperes
A capacitor is used in a ceiling fan to control the speed of the motor by altering the phase angle between the current and voltage. Capacitors help the motor to start and run smoothly at different speeds without drawing too much current. It also helps in reducing power consumption and improving the efficiency of the fan.
A 240V 3-phase motor is generally more efficient compared to a 120V single-phase motor of the same horsepower rating because it provides smoother and more consistent power delivery. The 3-phase motor also tends to have lower operating temperatures and reduced energy losses, resulting in higher efficiency and better performance overall.
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
A 0.75 kW (750 W) single-phase motor operating at 220 V will typically have a full-load running current of about 3.4 A, calculated using the formula ( I = \frac{P}{V} ) (where ( P ) is power in watts and ( V ) is voltage). The starting current, or inrush current, can be significantly higher, often ranging from 4 to 7 times the running current, depending on the motor type and load conditions. Therefore, the starting current could be approximately 13.6 A to 23.8 A.
To calculate the current per phase, use the formula: Current (I) = Power (P) / (Square Root(3) x Voltage (V)). For an 18kW motor at 415V, the current per phase will be: 18,000W / (1.732 x 415V) ≈ 24.5A per phase.
question is incomplete, I think you ask how much current consumed by this motor. for starting this motor we need a star/delta starter and a three phase supply.
P=VI P=power V=voltage I=current therefore current drawn is 5000/400=50/4=12.5 amperes
The wiring should allow for 115 amps.
118.72 amp current will be consumedAnswerFirst of all, 70 horsepower is the machines output, not its input, so you cannot calculate its current without knowing its efficiency. Secondly, the current also depends on the type of motor -is it a.c. or d.c? Is it single-phase or three-phase? Without this information, your question cannot be answered.
i think the answer is more on economical reasons ( 220v in the phil ).. since Voltage is inversely proportional to current..the higher the voltage, the lower the current..the lower the current, the smaller the electrical cable to use. In short, if we used 220v, electrical cable to be used is much smaller compared to the cable used in 110v..Smaller cable means less price than of the much larger cable.. :))
A capacitor is used in a ceiling fan to control the speed of the motor by altering the phase angle between the current and voltage. Capacitors help the motor to start and run smoothly at different speeds without drawing too much current. It also helps in reducing power consumption and improving the efficiency of the fan.
Current = Voltage / resistance (more properly impedance) so the current will be 220/55 or 4 amps.
Probably not. The single phase three horse power motor will be much larger in physical size than its three phase counterpart, and will probably not fit.
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Power in a 3 phase circuit is given by W=√3*V*I*cosφ therefore transposing the formula gives: I=W/√3*V*cosφ where I=current in amps, W=power in watts, V=line voltage, cosφ=power factor (this should be on the motor plate, if not you could use 0.9) Regards ninenix