Basically,
Power = Current*Voltage
Current = Power/Voltage
Current = 15/120
Current = 0.125A or 125mA
In the United States, the standard voltage for household current is 120 volts, so 123.4 volts would fall within an acceptable range. However, fluctuations in voltage can occur, so it's always a good idea to consult a professional if you are experiencing voltage irregularities.
To calculate the current in the AC circuit, we can use the formula P = V * I, where P is power (60 watts), V is voltage (120 volts), and I is current. Rearranging the formula to solve for current I, we get I = P / V. Plugging in the values, I = 60 watts / 120 volts = 0.5 amps. Therefore, the current flowing through the circuit is 0.5 amps.
To find the current, use the formula: Power (W) = Voltage (V) x Current (A). Rearrange the formula to solve for current: Current (A) = Power (W) / Voltage (V). Therefore, 160 watts divided by 120 volts equals 1.33 Amps.
Using the formula P = IV (power = current x voltage), you can rearrange it to solve for current: I = P/V. Plugging in the values, the current would be 0.25 amps (30 watts / 120 volts = 0.25 amps).
To find the current in amps, we can rearrange the formula for power: Power (W) = Current (A) x Voltage (V). Given 13.75 watts, if the voltage is 5V, then the current would be 2.75A (13.75 watts / 5 volts).
10 volts applied to 5 ohms would cause a current flow of 2 amperes. Current = voltage divided by resistance.
A circuit has an applied voltage of 100 volts and a resistance of 1000 ohms. The current flow in the circuit is 100v/1000ohms which would equal .1.
Can't tell without knowing resistance.
It is a voltage (potential) applied to a load that causes a current to flow through the load. Ohm's Law encapsulates this principal and states Volts = Current x Resistance. In your example, the applied voltage would be 200 volts.
You would get output when the intensity of the applied light is higher and series current would make the current amplitude higher.
If the wattage of a load is known then the current can be calculated. Watts equals amps times volts. You would use the following formula, Amps = Watts/Volts.
It depends on the current in amps. The watts would be equal to 5 times the current, because watts equals amps times volts.
The current's power factor is the true power divided by the apparent power. The Apparent Power is the volts multiplied by the amps. In this example, the ratio would be 200/253, or approximately .79.
9 volts====================The question is a bit convoluted.The power dissipated by the bulb and the current through itboth depend on the voltage applied across it.In the real world, the way to ask this question would have to be:If a light bulb dissipates 4.5 W of power when 0.5 A of currentpasses through it, what voltage has been applied across it ?(And, for extra credit, what is the bulb's effective resistance ?)
The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).The power in a resistor (in watts) is simply the product of the current (in amperes) times the voltage (in volts).
Ohm is the unit for electrical resistance. The definition is given by Ohm's Law: resistance = voltage / current; in SI units: ohms = volts / amperes. For example, a resistance of 1 ohm would result in 1 ampere of current for every volt applied.
In the United States, the standard voltage for household current is 120 volts, so 123.4 volts would fall within an acceptable range. However, fluctuations in voltage can occur, so it's always a good idea to consult a professional if you are experiencing voltage irregularities.