Copper(II) sulfate contain 398,1339 g copper in 1 kg CuSO4.
1 kg 250g is equal to 1250 grams.
0.807 kilograms weighs as much as 807 grams, as there are 1000 grams in a kilogram.
6,350,000 grams
105000 grams.
1000 g = 1 kgTo convert from g to kg, divide by 1000.
885x140=123900grams of copper sulphate per hour. If you are talking about using 885 gm of copper sulphate per ton of ore in the solution then the density of the copper sulphate(penta hydrate now because it's in water) is 2.284 gm per cm3 so that's 2.284x5=11.42gm per liter of solution, so 123900/11.42=10849.387 liters of copper sulphate(pentahydrate) per hour, NOTE:this is only how much copper sulphate is being used total in the solution which is 30% of the total liters used of solution because 25% of the water is inside the copper sulphate, the other 70% is just water. If you want the liters per hour of solution total, it is 34964.62 litres per hour of your 5% solution. I hope this was what you were looking for, I saw noone had answered and decided to try and get you what you needed.
The mass of 25 kg of anything is precisely 25 kg (25,000 grams).
9000 grams
1 kg 250g is equal to 1250 grams.
0.807 kilograms weighs as much as 807 grams, as there are 1000 grams in a kilogram.
1 kg = 1000 grams 1 gram = 0.001 kg
6,350,000 grams
655,000 grams
1000
To calculate the number of copper atoms in the statue, you first need to find the moles of copper present in 133 kg using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of copper to atoms.
1 kg = 1000 grams 1 gram = 0.001 kg
The recommended application rate for copper sulfate treatment of water is typically 0.005-0.02 ppm. For a 100,000 gallon dugout, you would need between 500-2000 grams (0.5-2 kg) of copper sulfate to achieve this concentration. It is important to consult with a water treatment professional for specific dosing instructions based on water quality and desired outcomes.