How much of each of 24 percent salt solution and 64 percent salt solution should be mix in order to produce 160ml that is a 43 percent salt solution?

Answer 1

Let's say the amount of 24% solution is A and that of 64% is B. We know from the clue A+B = 160ml. Out of A+B=160, we can get A=160-B We can express the solution as A.24/100 + B.64/100 = 160.43/100 to simplify multiply each term with 100 and we get 24A + 64B = 6880 to further simplify divide each term with 8 and we get 3A + 8B = 860 From the clue we know A = 160-B 3(160-B) + 8B = 860 480 - 3B + 8B = 860 5B = 860-480 5B = 380 B = 76ml A = 160-B A = 160- 76 A = 84 ml therefore the answer is * 84ml of 24% solution + 76 ml of 64% solution = 160ml of 43% solution

Answer 2

Let the amount of 24% salt solution be x ml and 64% salt solution be y ml. We know that x + y = 160 ml. In terms of salt content, 0.24x + 0.64y = 0.43(160). Solve these two equations simultaneously to find the values of x and y.