0
What else can I help you with?
How much Uranium 235 would remain after 4 half lives?
After one half-life, half of the original amount of Uranium-235 would remain. After four half-lives, only ( \frac{1}{2^4} ) or ( \frac{1}{16} ) of the original amount would be left. Therefore, if you started with 100 grams of Uranium-235, 6.25 grams would remain after four half-lives.
How much parent material will be left after five half-lives?
Only 1/32 of the original radioactive material will remain. (½)5 = 1/32
How much of one gram of radium-226 will remain unchanged after four half-lives?
After each half-life, half of the radium-226 will decay. Therefore, after four half-lives, 1/2^4 or 1/16th of the original gram of radium-226 will remain unchanged. This means that 1/16th of a gram, or 0.0625 grams, will still be unchanged after four half-lives.
How much sample of 10g of tritium with half life of 12.32 after 2 half lives?
After 2 half-lives (two half-lives of tritium is 12.32 x 2 = 24.64 years), the initial 10g sample of tritium would have decayed by half to 5g.
If a radioactive element half life is 500000 years given 20 grams of the element how much is left after 4 half lives?
Just divide the original amount by 2, 4 times: 10; 5; 2.5; 1.25. The final number is the answer.
How much Uranium 235 would remain after 4 half lives?
After one half-life, half of the original amount of Uranium-235 would remain. After four half-lives, only ( \frac{1}{2^4} ) or ( \frac{1}{16} ) of the original amount would be left. Therefore, if you started with 100 grams of Uranium-235, 6.25 grams would remain after four half-lives.
How much parent material will be left after five half-lives?
Only 1/32 of the original radioactive material will remain. (½)5 = 1/32
How much of one gram of radium -226 will remain unchanged after four half lives?
1g (1/2)4 = 1/16 g
The half-life of radium-226 is 1620 years. How much of one gram of radium-226 will remain unchanged after four half-lives?
After 4 half-lives, the amount remaining is ( (1/2)^4 ), which equals 1/16. Therefore, 1 gram of radium-226 will have 1/16 gram unchanged after four half-lives, which is 0.0625 grams.
After three half lives have passed how much of the original radioactive material will remaim?
After three half-lives, 12.5% of the original radioactive material will remain. Each half-life reduces the amount of material by half, so after three half-lives the remaining material will be 0.5^3 = 0.125 or 12.5%.
How much of one gram of radium-226 will remain unchanged after four half-lives?
After each half-life, half of the radium-226 will decay. Therefore, after four half-lives, 1/2^4 or 1/16th of the original gram of radium-226 will remain unchanged. This means that 1/16th of a gram, or 0.0625 grams, will still be unchanged after four half-lives.
A 200 gram sample having a half- life of 12 seconds would have how much remaining after 36 seconds?
To determine the remaining amount of a 200 gram sample after 36 seconds with a half-life of 12 seconds, we first calculate how many half-lives fit into 36 seconds. There are three half-lives in 36 seconds (36 ÷ 12 = 3). Each half-life reduces the sample by half: after the first half-life, 100 grams remain; after the second, 50 grams; and after the third, 25 grams. Therefore, 25 grams of the sample would remain after 36 seconds.
After two half-lives, how much of the original material has decayed?
After two half-lives, 75% of the original material has decayed.
How much Cu-61 (half-life about 3 hours) would remain from 2 mg sample after 6 hours?
6 hours = 2 half lives, thus 25 % would remain. 0.25 x 2 mg = 0.5 mg.Done another way...fraction remaining = 0.5^n where n = number of half lives = 6hr/3hr = 2fraction remaining = 0.5^2 = 0.250.25 x 2 mg = 0.5 mg
How much sample of 10g of tritium with half life of 12.32 after 2 half lives?
After 2 half-lives (two half-lives of tritium is 12.32 x 2 = 24.64 years), the initial 10g sample of tritium would have decayed by half to 5g.
The half life of iron 59 is 44.5 days how much of 2mg sample will remain after 133.5 days?
After 133.5 days, there will be 0.125 mg of the 2 mg sample of iron-59 remaining. This can be calculated by taking into account each half-life period (44.5 days) and calculating the remaining amount after 3 half-lives (133.5 days).
The half-life of cobalt-60 is 5.3 years. If you start with 10.0 g of cobalt-60 how much will remain after 21.2 years?
To calculate the remaining amount of cobalt-60 after 21.2 years, we can use the half-life formula. Since the half-life is 5.3 years, we find the number of half-lives in 21.2 years by dividing 21.2 by 5.3, which is approximately 4.0 half-lives. After 4 half-lives, the remaining amount can be calculated as (10.0 , \text{g} \times \left(\frac{1}{2}\right)^4 = 10.0 , \text{g} \times \frac{1}{16} = 0.625 , \text{g}). Thus, 0.625 g of cobalt-60 will remain after 21.2 years.
