The half-life of Carbon-14 is 5,730 years. As such for the carbon-14 to decay from 100% to 12.5% it would take three times the half-life of the material.
100% (1st half life decay period) 50% (2nd half life decay period) 25% (3rd half life decay period) 12.5%.
Therefore = 5730 x 3 = 17,190 years.
1.6 g/ml
430 million years
P1V1=P2V2 VI=325ml P1=655mm Hg V2=125ml P2=? =655 x 325= P2 x 125 =(655 x 325)/ 125 =212875/125 =1703mm Hg. :)
We have now way of knowing unless we know the initial number of C-14
There will be 125 grams of radium left. Keep it simple. Ih a half-life, half the sample decays. Half of 1000 grams is 500 grams, then half of 500 grams is 250 grams. Half of that again is 125 grams. And just so you know, the half-life of radium-226, the non-synthetic isotope of radium, is 1602 years. If this was the case here, 4806 years would have to pass to get the sample to decay as far as it did.The remained quantity of radium after 3 x 1602 years is 125 grams.
125 percent into a percentage = 125%
98 is 78.4 percent of 125 122.5 is 98 percent of 125
125 percent percent of 48 = 0.6
It is 223.86
125 percent of 215000 = 268750
125% = 1.25
Answer this question…What is 75 of 125 as a percent?
92% = 0.920.92 * 125 = 115
30 percent of 125 = 125 *30/100 = 37.5 125 - 37.5 = 87.5
80 percent of 125 is 100.
10 + (125 percent) = 22.5
125 = 12,500%