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How would the following observations affect the calculated percent composition of each component if there is a small amount of white powder left in the sample container after heating the contents to t?
If there is a small amount of white powder left in the sample container after heating, it suggests incomplete decomposition of the sample. This would lead to an underestimation of the percent composition of the volatile components, as not all of it would have been driven off during heating. The remaining white powder could be a non-volatile component, affecting the overall calculation of percent composition.
At sample of 131 I decays to 1.0 grams in 40 days. What was the mass of the original sample?
To determine the original mass of the iodine-131 sample, we can use the radioactive decay formula, which states that the remaining mass can be calculated using the equation ( N(t) = N_0 e^{-\lambda t} ). Given that the sample decays to 1.0 grams in 40 days, and knowing the half-life of iodine-131 is approximately 8 days, we can calculate the decay constant and then find the original mass ( N_0 ). After performing the calculations, the original mass of the iodine-131 sample was approximately 5.6 grams.
What is the total mass of a 10. gram sample of 42k that will remain unchanged after 12.4 hours?
To determine the remaining mass of a 10-gram sample of (^{42}\text{K}) after 12.4 hours, we need to know its half-life. The half-life of (^{42}\text{K}) is approximately 12.36 hours. After 12.4 hours, which is slightly more than one half-life, the mass will be reduced to about half of the initial mass. Thus, approximately 5 grams of the original 10-gram sample will remain unchanged after 12.4 hours.
How old in years is a fossil sample that has 12.5 percent C-14?
The half-life of Carbon-14 is 5,730 years. As such for the carbon-14 to decay from 100% to 12.5% it would take three times the half-life of the material.100% (1st half life decay period) 50% (2nd half life decay period) 25% (3rd half life decay period) 12.5%.Therefore = 5730 x 3 = 17,190 years.
How old is a sample of wood with 75 percent of 14 Carbon how old is the sample t125730 years?
t is equal to = (1/2)ln(A/A0))
How much of an 80-milligram sample of Iodine-131 would be left after 32 days?
After 32 days, approximately 5 milligrams of the 80-milligram sample of Iodine-131 would be left. Iodine-131 has a half-life of about 8 days, so after each 8-day period, half of the remaining sample will decay.
If a sample of radioactive materiel contains 17 daughter nuclide what percent of parent nuclide is present in the sample?
If there are 17 daughter nuclides, then this represents 17 half-lives. Each half-life corresponds to a 50% reduction in the parent nuclide. Therefore, 17 half-lives would result in 1/2^17 (0.0000763) or approximately 0.00763% of the original parent nuclide remaining in the sample.
What is the percent composition of NaHCO3 in a given sample?
To find the percent composition of NaHCO3 in a sample, you would calculate the mass of NaHCO3 in the sample divided by the total mass of the sample, then multiply by 100 to get the percentage.
How to find the percent by mass of a compound in a given sample?
To find the percent by mass of a compound in a given sample, you need to divide the mass of the compound by the total mass of the sample and then multiply by 100. This will give you the percentage of the compound in the sample.
When you draw a sample from a normal distribution what can you conclude about the sample distribution?
The answer depends on how the sample is selected. If it is a simple random sample, of size n, then it is distributed approximately normally with the same mean as the population mean.The answer depends on how the sample is selected. If it is a simple random sample, of size n, then it is distributed approximately normally with the same mean as the population mean.The answer depends on how the sample is selected. If it is a simple random sample, of size n, then it is distributed approximately normally with the same mean as the population mean.The answer depends on how the sample is selected. If it is a simple random sample, of size n, then it is distributed approximately normally with the same mean as the population mean.
How would the following observations affect the calculated percent composition of each component if there is a small amount of white powder left in the sample container after heating the contents to t?
If there is a small amount of white powder left in the sample container after heating, it suggests incomplete decomposition of the sample. This would lead to an underestimation of the percent composition of the volatile components, as not all of it would have been driven off during heating. The remaining white powder could be a non-volatile component, affecting the overall calculation of percent composition.
A sample of radioactive isotope has a halflife of 1 day how much of the original sample will be left at the end of the fourth day?
If a sample of radioactive material has a half-life of one week the original sample will have 50 percent of the original left at the end of the second week. The third week would be 25 percent of the sample. The fourth week would be 12.5 percent of the original sample.
The half-life of actinium 227 is 21.772 years After 50 years how much of a 1500 g sample will remain radioactive?
After 50 years, 1500 g of actinium-227 will have undergone approximately 2.3 half-lives (50 years / 21.772 years per half-life). This means that approximately 25% (50% decayed after 1 half-life, and 50% of the remaining amount decays after the second half-life) of the original sample will remain radioactive, so there will be around 375 g of actinium-227 remaining.
What s coefficient of curvature in soil mechanics?
Cc = (D30)^2 / (D10 * D60) Where: * D60 is the particle-size diameter for which 60 percent of the sample was finer, and, * D30 is the particle-size diameter for which 30 percent of the sample was finer. * D10 is the particle-size diameter for which 10 percent of the sample was finer.
What is a 10 percent sample of 250 people?
25 people
When the sample size and sample standard deviation remain the same a 99 percent confidence interval for a population mean will be narrower than the 95 percent confidence interval for the mean?
Never!
What is the total mass of a 10. gram sample of 42k that will remain unchanged after 12.4 hours?
To determine the remaining mass of a 10-gram sample of (^{42}\text{K}) after 12.4 hours, we need to know its half-life. The half-life of (^{42}\text{K}) is approximately 12.36 hours. After 12.4 hours, which is slightly more than one half-life, the mass will be reduced to about half of the initial mass. Thus, approximately 5 grams of the original 10-gram sample will remain unchanged after 12.4 hours.
