Not exactly sure what you mean about "aluminum's half life equation." Exponential decay, from where we get the half-life equation from, has nothing to do with mass, atomic number, etc... and therefore has nothing to do with any particular isotope.
No, the equation is not balanced. The correct balanced equation would be: 2Na + F2 -> 2NaF
This is not an equation at all. An example of a correct (and balanced) equation would be: 2H2 + O2 --> 2 H2O
To balance the unbalanced chemical equation involving aluminum oxide (Al₂O₃), you need to ensure that the number of atoms of each element is the same on both sides of the equation. Without the specific equation provided, I can't give the exact coefficient for Al₂O₃. However, in typical reactions involving Al₂O₃, the coefficient could vary based on the reactants and products involved. Once the equation is balanced, you would determine the coefficient for Al₂O₃ from that specific context.
This is not 'the balanced equation' of MgSO, what is meant is the chemical FORMULA of magnesium sulfate or magnesium sulfite.These are: MgSO4 and MgSO3respectively.
The balanced equation for the formation of silver iodide is: 2 AgNO3 + 2 KI → 2 AgI + 2 KNO3
To determine the number of aluminum atoms on each side of a balanced equation, you would need to examine the coefficients of the aluminum-containing compounds in the equation. Then, multiply the coefficient by the number of aluminum atoms in each compound. For example, in the equation 2Al + 3CuO → Al2O3 + 3Cu, there are 2 aluminum atoms on each side.
The balanced chemical equation for the reaction between aluminum and oxygen to form aluminum oxide is: 4Al + 3O2 → 2Al2O3. From the balanced equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Therefore, if 3.40 mol of aluminum and 2.85 mol of oxygen are reacted, the limiting reactant is oxygen. Thus, 3.40 mol of aluminum would theoretically produce 1.90 mol of aluminum oxide.
No, the equation is not balanced. The correct balanced equation would be: 2Na + F2 -> 2NaF
This is not an equation at all. An example of a correct (and balanced) equation would be: 2H2 + O2 --> 2 H2O
To write a balanced equation for sulfur reacting with metals to form ionic compounds with S2- ions, you would need to consider the valency of the metal involved. For example, with sodium (Na), the balanced equation would be: 2Na + S → Na2S. The coefficients are adjusted to balance the charge on each side of the equation.
To balance the unbalanced chemical equation involving aluminum oxide (Al₂O₃), you need to ensure that the number of atoms of each element is the same on both sides of the equation. Without the specific equation provided, I can't give the exact coefficient for Al₂O₃. However, in typical reactions involving Al₂O₃, the coefficient could vary based on the reactants and products involved. Once the equation is balanced, you would determine the coefficient for Al₂O₃ from that specific context.
The balanced chemical equation for the reaction between aluminum and oxygen is 4Al + 3O2 → 2Al2O3. Using the stoichiometry of the equation, you would need 50 g of aluminum to react with 75 g of oxygen, since the molar ratio between Al and O2 is 4:3.
Burning of aluminum in oxygen (air): 4Al + 3O2 → 2Al2O3
The chemical equation is not balanced. A balanced equation would be: KOH + H2SO4 -> KHSO4 + H2O
This is not 'the balanced equation' of MgSO, what is meant is the chemical FORMULA of magnesium sulfate or magnesium sulfite.These are: MgSO4 and MgSO3respectively.
No, the balanced equation for the reaction between V2O5 and CaS would be: V2O5 + 5CaS -> 5CaO + V2S5
The balanced equation for AI(NO3)3 is not provided, but in a typical chemical equation, the coefficient for AI(NO3)3 would be 1.