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I just had this question on my chem homework so I'll see if I can help.
First thing you need to do is balance the equation. The balanced equation should look like this:
2NaHCO3 -----> Na2CO3 + H2O +CO2
With that out of the way we can start converting.
The Molar Mass of NaHCO3 is 84 (or close to it, depending on how you round your decimals) So we do 5g NaHCO3/ 84g NaHCO3. That should give you about 0.059. Next we do 0.059/2mol NaHCO3, because we know from the balanced equation that we have a 2:1:1:1 ratio. That should give you about 0.0295. Now we find the Molar Mass of CO2, which is around 44. Lastly, we go 0.0295x44 and that should give us the answer.
I got 1.3g of CO2 as my answer. I hope I was able to be of some use. :)
What else can I help you with?
How many grams of carbon dioxide is produced from the combustion of B grams of hexane?
The combustion of hexane (C6H14) produces carbon dioxide (CO2) according to the reaction: C6H14 + 7O2 → 6CO2 + 7H2O. For every 1 gram of hexane burned, approximately 3.03 grams of carbon dioxide are produced. Therefore, from the combustion of B grams of hexane, the amount of carbon dioxide produced would be approximately 3.03B grams.
What is the mass of 1 mole of carbon monoxide?
One mole of 12C has a mass of 12.00000 grams (exactly, by definition).One mole of 13C has a mass of 13.00335 grams.One mole of 14C has a mass of 14.00324 grams.One mole of natural carbon - i.e. a sample with the ration of isotopes equal to that in nature - has a mass of 12.0107 grams.
If we want to form 20.2 grams carbon dioxide how many grams of oxygen do we need?
We need 14,8 g oxygen.
Does carbon dioxide and oxygen have mass?
Yes. CO2 has a weight of 44g/mol and O2 has a weight of 32g/mol.
What mass of NaHCO3 is needed to neutralize 150ml of 044M HCl?
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
How many grams of each product are produced by the decomposition of 42.0 grams of baking soda?
When 42.0 grams of baking soda (sodium bicarbonate, NaHCO3) decomposes, it produces 22.0 grams of sodium carbonate (Na2CO3) and 20.0 grams of carbon dioxide (CO2) gas.
If a typical antacid tablet contains 2 grams of sodium hydrogen carbonate how many moles of carbon dioxide should one tablet yield?
NaHCO3 = 84.007 g/mol Figure out the mole fraction = 2g / 84.007 g/mol The unit of the answer is mol, which in this context is the same as mole. Since you only have one carbon in NaHCO3 you cannot have more moles of CO2 than moles of NaHCO3.
How much carbon can 22 grams of carbon dioxide make?
22 grams of carbon dioxide contains 12 grams of carbon. This amount of carbon can combine with 32 grams of oxygen to form 44 grams of carbon dioxide.
How many moles of carbon dioxide are there in 19 grams of carbon dioxide?
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
What volume of carbon oxide is eliminated at the action of diluted sulfuric acid with 100 gram of food soda NaHCO3 and 100 gram soda of Na2HCO3?
When 100 grams of NaHCO3 (sodium bicarbonate) and 100 grams of Na2CO3 (sodium carbonate) react with diluted sulfuric acid, carbon dioxide gas will be produced. The balanced chemical equations are: 2NaHCO3 + H2SO4 -> Na2SO4 + 2H2O + 2CO2 Na2CO3 + H2SO4 -> Na2SO4 + H2O + CO2 The amount of carbon dioxide gas generated can be calculated using stoichiometry with the given masses of NaHCO3 and Na2CO3.
When there are 3 grams of carbon and 8 grams of oxygen if all of the carbon and oxygen reacted how many grams of carbon dioxide are produced?
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
The are 6 grams of carbon and 20 grams of oxygen if 22 grams of carbon dioxide are produced and all the carbon is used how many grams of oxygen are left?
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
What is the mass of carbon in carbon dioxide?
The mass of carbon in carbon dioxide is 12 grams per mole.
How many grams of carbon dioxide are in a 2 liter of sprite?
A 2-liter bottle of Sprite contains about 5.3 grams of carbon dioxide.
How many grams of carbon dioxide is in sprite?
A 12-ounce can of Sprite contains approximately 19 grams of carbon dioxide, which is used to carbonate the beverage.
How many moles of carbon are there from the original sample of 11.0 grams of carbon dioxide and 4.50 grams of water with a combustion of 7.50 grams?
Look up the molecular weight of carbon dioxide in the periodic table. The formula for carbon dioxide is CO2, which means one atom of carbon and two atoms or oxygen per molecule of carbon dioxide. Carbon has molecular weight of 12. Oxygen molecular weight is 16. Total 12+16+16= 44 11 grams/44 grams/mole=0.25 moles of carbon The grams of water and combustion of 7.5 grams are totally irrelevant. They are only given to possibly confuse you.
