If you start with 3 cells and assume each cell divides into 2 cells in each generation, you would have 3 cells in the first generation. In the second generation, that would double to 6 cells, and in the third generation, it would double again to 12 cells. Thus, after 3 generations of divisions, you would have a total of 12 cells.
To determine how long it would take for 10 E. coli cells to grow to 320 cells, we can use the exponential growth model of bacteria. E. coli typically divides every 20 minutes under optimal conditions. Starting with 10 cells, the population would double every 20 minutes. After 3 generations (60 minutes), the population would reach 80 cells, and after 4 generations (80 minutes), it would grow to 160 cells. Finally, after 5 generations (100 minutes), it would reach 320 cells. Thus, it would take approximately 100 minutes for 10 E. coli cells to reach 320 cells.
16. The number doubles at each division.
If cells split in half, and do not die, then you have:1 --> 2 --> 4 --> 8 ...20 --> 21 --> 22 --> 23 ...Ok, so let's assume the first generation has 1 cell...So the 20th generation would have 219 (2(20-1)) cells.So you would get 524,288 cells in the 20th generation, or 1,048,576 cells in the 21st generation.I suppose I might actually take the 1,048,576 number as being the 21st generation is AFTER 20 generations.
At the end of three mitotic divisions, there will be a total of 8 cells. This is because the number of cells double with every division. At the end of the first mitotic division, there are daughter cells. At the end of the second division: daughter cells further divide into two cells, giving 4 cells. At the end of the third division: each of the four cells further divide into 2 cells each, resulting in a total of 8 cell.
There would be 32 cells after 5 hours. This is calculated by realizing that 5 hours is equivalent to 10 generations (5 hours / 30 minutes per generation), and each cell doubles in number in each generation (2^10 = 32).
Starting with a zygote, a series of five cell divisions would produce an early embryo with 32 cells. Each division doubles the number of cells, so the progression would be 1 -> 2 -> 4 -> 8 -> 16 -> 32 cells.
To determine how long it would take for 10 E. coli cells to grow to 320 cells, we can use the exponential growth model of bacteria. E. coli typically divides every 20 minutes under optimal conditions. Starting with 10 cells, the population would double every 20 minutes. After 3 generations (60 minutes), the population would reach 80 cells, and after 4 generations (80 minutes), it would grow to 160 cells. Finally, after 5 generations (100 minutes), it would reach 320 cells. Thus, it would take approximately 100 minutes for 10 E. coli cells to reach 320 cells.
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wat up
16. The number doubles at each division.
If cells split in half, and do not die, then you have:1 --> 2 --> 4 --> 8 ...20 --> 21 --> 22 --> 23 ...Ok, so let's assume the first generation has 1 cell...So the 20th generation would have 219 (2(20-1)) cells.So you would get 524,288 cells in the 20th generation, or 1,048,576 cells in the 21st generation.I suppose I might actually take the 1,048,576 number as being the 21st generation is AFTER 20 generations.
It would take about 40 consecutive mitotic cell divisions for one zygote to grow into an organism with 100 trillion cells. This is because each cell division doubles the number of cells, so 2^40 is approximately equal to 100 trillion.
At the end of three mitotic divisions, there will be a total of 8 cells. This is because the number of cells double with every division. At the end of the first mitotic division, there are daughter cells. At the end of the second division: daughter cells further divide into two cells, giving 4 cells. At the end of the third division: each of the four cells further divide into 2 cells each, resulting in a total of 8 cell.
an error in DNA replication would affect many generations of cells
500 cell divisions. Why? Because 500x2=1000. You also could have found the answer by just doing 1000 divided by 2. Which equals obviously 500.
to what extent would sociologists agree that ethnic divisions are imoprtant than class divisions in Britain today?
Assuming one division of a cell results in two cells, 20 divisions would be necessaryTHE LONG WAY1 -> 22 -> 44 -> 88 -> 1616 -> 3232 -> 6464 -> 128128 -> 256256 -> 512512 -> 1,0241,024 -> 2,0482,048 -> 4,0964,096 -> 8,1928,192 -> 16,38416,384 -> 32,76832,768 -> 65,53665,536 -> 131,072131,072 -> 262,144262,144 -> 524,288524,288 -> 1,048,576THE SHORT WAYlog(1,000,000) / log(2) = 19.9316 = 20 [partial divisions not allowed]