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If the purple allele (p) is dominant, then the red phenotype must be associated with the recessive allele, which we can represent as q. Given that 76 out of 100 plants are red, this means that 24 are purple. Assuming Hardy-Weinberg equilibrium, the frequency of the red phenotype (q^2) is 0.76, so q is the square root of 0.76, which is approximately 0.87. Therefore, the frequency of the purple allele (p) is 1 - q, which is roughly 0.13.

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In a certain population of rabbits the allele for brown fur is dominant over the allele for white fur. If 10 out of 100 rabbits have white fur what is the allele frequency for the dominant allele?

In the population of 100 rabbits, 10 have white fur, indicating that they are homozygous recessive (aa). This means that the frequency of the recessive allele (a) can be calculated using the formula ( q^2 = \frac{10}{100} = 0.1 ), so ( q = \sqrt{0.1} \approx 0.316 ). The frequency of the dominant allele (A) is then ( p = 1 - q \approx 1 - 0.316 = 0.684 ). Thus, the allele frequency for the dominant allele is approximately 0.684.


What is the genotype and phenotype ratios for a homozygous dominant female and a homozygous resessive male?

When a homozygous dominant female (genotype AA) is crossed with a homozygous recessive male (genotype aa), all offspring will inherit one dominant allele from the mother and one recessive allele from the father, resulting in a genotype of Aa for all offspring. The phenotype ratio will show all offspring displaying the dominant trait. Thus, the genotype ratio is 100% Aa, and the phenotype ratio is 100% expressing the dominant trait.


What is the probabilty that the offspring of a homozygous domiant idiviual and a homozygous recessive indiviual will exbhit the domaint phenotype?

If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.


If there are 19 plants with rough seeds in a population of 100 what is the allele frequency for smooth seeds?

The frequency of dominant which is smooth seed early is 0.556 or 6%.


In a certain population of rabbits the allele for brown fur is dominant over the allele for white fur. If 20 out of 100 rabbits have white fur what is the allele frequency for the recessive allele?

In this population, 20 out of 100 rabbits have white fur, indicating they are homozygous recessive (bb). The frequency of the recessive genotype (bb) is 0.20. Using the Hardy-Weinberg principle (p² + 2pq + q² = 1), we know q² = 0.20, so q (the frequency of the recessive allele) is the square root of 0.20, which is approximately 0.447. Thus, the allele frequency for the recessive allele is about 0.447.

Related Questions

A fly has two alleles for the color of its eyes. The green allele is recessive, and is represented by q. The blue allele is dominant, and is represented by p. If 44 of 100 organisms are green, what is P?

, 0.34 Apex


A plant has two alleles for color. The red allele is recessive and is represented by q. The purple allele is dominant and is represented by p. If 59 of 100 organisms are red what is q?

.77


A fly has two alleles for the color of its eyes The green allele is recessive and is represented by q The blue allele is dominant and is represented by p If 20 of 100 organisms are green what is?

A. 0.45 Apex


A parent that is homozygous for a dominant trait is crossed with a parent that is homozygous for the recessive trait What percentage of the offspring will display the dominant trait?

100% of the offspring will display the dominant trait because the homozygous dominant parent can only pass on the dominant allele. The offspring will inherit one dominant allele from the dominant parent and one recessive allele from the recessive parent, resulting in a heterozygous genotype expressing the dominant trait.


In a certain population of rabbits the allele for brown fur is dominant over the allele for white fur. If 10 out of 100 rabbits have white fur what is the allele frequency for the dominant allele?

In the population of 100 rabbits, 10 have white fur, indicating that they are homozygous recessive (aa). This means that the frequency of the recessive allele (a) can be calculated using the formula ( q^2 = \frac{10}{100} = 0.1 ), so ( q = \sqrt{0.1} \approx 0.316 ). The frequency of the dominant allele (A) is then ( p = 1 - q \approx 1 - 0.316 = 0.684 ). Thus, the allele frequency for the dominant allele is approximately 0.684.


A fly has two alleles for the color of its eyes The green allele is recessive and is represented by q The blue allele is dominant and is represented by p If 71 of 100 organisms are green what is?

0.16


What is an example of allele frequency?

An example of allele frequency is when in a population of 100 individuals, 60 individuals have the dominant allele (A) for a specific gene, while 40 individuals have the recessive allele (a). The frequency of the dominant allele (A) would be 0.6, and the frequency of the recessive allele (a) would be 0.4.


A fly has two alleles for the color of its eyes. The green allele is recessive and is represented by q. The blue allele is dominant and is represented by p. If 11 of 100 organisms are green what is qt?

To find q (the frequency of the green allele), use the Hardy-Weinberg equation: p^2 + 2pq + q^2 = 1. Given that 11% are green, q^2 = 0.11. Therefore, q = √0.11 ≈ 0.33.


What is the genotype and phenotype ratios for a homozygous dominant female and a homozygous resessive male?

When a homozygous dominant female (genotype AA) is crossed with a homozygous recessive male (genotype aa), all offspring will inherit one dominant allele from the mother and one recessive allele from the father, resulting in a genotype of Aa for all offspring. The phenotype ratio will show all offspring displaying the dominant trait. Thus, the genotype ratio is 100% Aa, and the phenotype ratio is 100% expressing the dominant trait.


Freckles are a dominant characteristic The appearance of freckles is the phenotype what represents a heterozygous genotype for freckles?

If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.


What is the probabilty that the offspring of a homozygous domiant idiviual and a homozygous recessive indiviual will exbhit the domaint phenotype?

If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.


If there are 19 plants with rough seeds in a population of 100 what is the allele frequency for smooth seeds?

The frequency of dominant which is smooth seed early is 0.556 or 6%.