RrYy. This is because the first parent is homozygous dominant for both traits (R and Y), while the second parent is homozygous recessive for both traits (r and y). Therefore, all offspring will inherit one dominant allele (R and Y) and one recessive allele (r and y) for each trait.
In pea plants, round seeds are dominant (R) over wrinkled seeds (r), and yellow seeds are also dominant (Y) over green seeds (y). A hybrid round pure yellow pea would have the genotype RrYY, where "Rr" indicates it is heterozygous for the round seed trait and "YY" indicates it is homozygous for the yellow seed trait.
Yes, males can be homozygous for traits that are located on the sex chromosomes, such as the X and Y chromosomes. For example, a male could be homozygous for a trait on the X chromosome if he inherits the same allele from both his mother and father.
When there is only one recessive allele present for a characteristic, the dominant allele will be expressed in the phenotype. The individual will exhibit the trait associated with the dominant allele, while still carrying the recessive allele in their genetic makeup.
No, sex chromosomes are not referred to as homozygous chromosomes. Homozygous chromosomes have identical alleles at a specific gene locus, while sex chromosomes determine an individual's biological sex. In humans, sex chromosomes include X and Y chromosomes.
RrYy. This is because the first parent is homozygous dominant for both traits (R and Y), while the second parent is homozygous recessive for both traits (r and y). Therefore, all offspring will inherit one dominant allele (R and Y) and one recessive allele (r and y) for each trait.
if for example we had a yellow and a blue flower yellow being dominant (Y) and blue being recessive (y) a homozygous organism has the phenotype of either being YY or yy and a heterozygous organism could only be Yy.
The genotype for round green peas is typically represented as "RRyy," where "R" stands for the dominant allele for round shape and "y" represents the recessive allele for yellow color. In this case, the round shape is dominant over the wrinkled shape, while green color is recessive to yellow. Thus, the round green peas are homozygous for the round shape and homozygous recessive for the color trait.
Let Y represent the dominant allele, and yrepresent the recessive allele. Let us also assume that "pure" means homozygous for that trait ("pure' is not the usual term for this, "homozygous" is) So, the two genotypes of the parents of the cross are: Parent 1: YY Parent 2: yy To solve a problem like this, one always has to determine what kind(s) of gametes each parent can produce. Both parents are homozygous for their respective traits, so in this case, each parent can only produce one kind of gamete: Parent 1 can only produce Ygametes, and Parent 2 can only produce y gametes. Therefore, every one of their offspring will have the following genotype: Yy Since every one of the offspring of the cross carries a Y allele, and Y is dominant, all of the offspring will be yellow.
When crossing two heterozygous pea plants (Yy x Yy) using a Punnett square, the resulting genotypes are YY, Yy, Yy, and yy. This results in a 1:2:1 genotype ratio, where 25% of the offspring will be homozygous dominant (YY), 50% will be heterozygous (Yy), and 25% will be homozygous recessive (yy). The phenotypic ratio will be 3 yellow (YY and Yy) to 1 green (yy).
In pea plants, round seeds are dominant (R) over wrinkled seeds (r), and yellow seeds are also dominant (Y) over green seeds (y). A hybrid round pure yellow pea would have the genotype RrYY, where "Rr" indicates it is heterozygous for the round seed trait and "YY" indicates it is homozygous for the yellow seed trait.
An allele on either X or Y could be dominant over the allele on the other chromosome, but it is more common for the allele on the X to be dominant, because the Y chromosome is much smaller than the X and contains fewer genes. In many cases, there is no allele for a particular gene on the Y chromosome; so whatever allele is on the Y will be dominant.
Yes, males can be homozygous for traits that are located on the sex chromosomes, such as the X and Y chromosomes. For example, a male could be homozygous for a trait on the X chromosome if he inherits the same allele from both his mother and father.
You will need to place the genetic combination possibilities into at least two Punnett Squares where Y=dominant yellow and g=recessive green symbols are assigned . Observe the outcome of the crosses which should reflect a specific probablity of results shown as follows: YY X gg yields 100% Yg heterozygous combinations with yellow appearance and could be dominant but further experimentation is needed to confirm. Yg X gg yields 50% heterozygous offspring (yellow appearance) with 50% homozygous (green appearance). If other results are observed after these two genetic combinations then yellow is not dominant to green. Lastly comparing the results between the two crosses will help you narrow the distinction between homozygous and heterozygous characteristics. Research: Punnett Squares further if you are not familiar with its dynamics. Good luck!
When there is only one recessive allele present for a characteristic, the dominant allele will be expressed in the phenotype. The individual will exhibit the trait associated with the dominant allele, while still carrying the recessive allele in their genetic makeup.
No, sex chromosomes are not referred to as homozygous chromosomes. Homozygous chromosomes have identical alleles at a specific gene locus, while sex chromosomes determine an individual's biological sex. In humans, sex chromosomes include X and Y chromosomes.
Male as the Y chromosome is dominant