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If the container decreases in size, the pressure inside the container will increase. This is because the gas molecules are more confined and collide more frequently with the walls of the container. The amount of gas remains constant, but the pressure changes due to the reduced volume.
If the size of the container is increased atoms have further to travel between collisions with the wall so collisions are less frequent and thus the pressure exerted is reduced.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
Pressure is due to the bombardment of molecules on the walls of the container. So when the volume is reduced then naturally the surface area will be reduced. Pressure is the force measured per unit area. Hence reducing volume would bring a decrease in its surface area and so the pressure increases. So volume and pressure are getting related.
If the intermolecular space of a gas is reduced, the gas will experience an increase in pressure and become more dense. As the molecules are brought closer together, they will collide more frequently with each other and the container walls, resulting in a higher pressure.
This problem can be solved with the ideal gas law. The original pressure and volume of the container are proportional the final pressure and volume of the container. The original pressure was 1 atmosphere and the original volume was 1 liter. If the final volume is 1.8 liters, then the final pressure is 0.55 atmospheres.
If the volume of a container of air is reduced, the pressure of the air inside the container will increase. This is because the volume and pressure of a gas are inversely proportional according to Boyle's Law. The particles inside the container will collide more frequently with the walls, leading to an increase in pressure.
If the volume of a container of gas is reduced, the pressure inside the container will increase. This is because reducing the volume decreases the amount of space the gas molecules have to move around, leading to them colliding more frequently with the walls of the container, thus increasing the pressure.
Yes. You can, for example, boil water at room temperature if you apply a vacuum pump to the container. However, if it was ONLY a sealed container (reduce the pressure and then take the vacuum pump away), the vapor increases the pressure and the whole thing comes to equilibrium and stops boiling.
If the container decreases in size, the pressure inside the container will increase. This is because the gas molecules are more confined and collide more frequently with the walls of the container. The amount of gas remains constant, but the pressure changes due to the reduced volume.
it doublesIf the mass of the air remains constant, the PPO2 doubles.
initial volume = V1 final volume = V2 initial pressure = P1 final pressure = P2 = (1/2)P1 P1V1 = P2V2 P1V1 = (1/2)P1V2 P1 cancels; V1 = (1/2)V2 V2 = 2V2.
If the size of the container is increased atoms have further to travel between collisions with the wall so collisions are less frequent and thus the pressure exerted is reduced.
As the volume is decreased, the same number of molecules of air have a smaller space to move freely in. The number of collisions of molecules of air with the walls of the container per unit time increases. Since pressure is the force exerted over an area, the pressure increases.
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
The pressure is reduced to one third of the original pressure. The pressure will stay the same you are only changing the volume
"For a fixed mass of ideal gas at fixed temperature, the product of pressure and volume is a constant." This means that if you have a container with an ideal gas in it, and the container is closed so that no gas can escape or get int (i.e. the mass of the gas contained is constant), when you raise the volume of the container by some ratio, the pressure will be reduced by the same ratio. So if you triple the volume, the pressure will be reduced to a third of its original value. And if you quadruple the pressure, the volume will go down by a factor of 4.