answersLogoWhite

0

According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Given that the unknown gas effuses at half the speed of oxygen (32 g/mol), we can set up the ratio: ( \frac{r_{\text{unknown}}}{r_{\text{O}2}} = \sqrt{\frac{M{\text{O}2}}{M{\text{unknown}}}} ). Since the unknown gas effuses at half the speed, ( \frac{1}{2} = \sqrt{\frac{32}{M_{\text{unknown}}}} ), squaring both sides gives ( \frac{1}{4} = \frac{32}{M_{\text{unknown}}} ), leading to ( M_{\text{unknown}} = 128 ) g/mol. Therefore, the unknown gas likely has a molar mass of 128 g/mol.

User Avatar

AnswerBot

1w ago

What else can I help you with?