B
Carbon is the sixth element with a total of 6 electrons. In writing the electron configuration for carbon the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for C goes in the 2s orbital. The remaining two electrons will go in the 2p orbital. Therefore the C electron configuration will be 1s2 2s2 2p2.
Neon has 10 electrons, so its orbital diagram would show two electrons in the 1s orbital, two in the 2s orbital, and six in the 2p orbital (with one electron in each of the three 2p orbitals). Each orbital can hold a maximum of 2 electrons with opposite spins.
It would be the next Alkali Metal and would be placed under Francium.
No, that electron configuration does not exist. After the 3p orbital fills with electrons, the next lowest energy orbital is 4s. After 4s contains 2 electrons, then 3d can accept electrons, upto 10. The element with this electron configuration is zinc, one of the transitional metals. Although 3d is full, those electrons can be 'valence' electrons and given to non-metals to form ions, such as Zn+2 or Zn+4. So 3d really acts like a 4th shell orbital and will still be quite reactive even when full. To see just how reactive these electrons are, look at the youtube videos embedded in this site: http://www.chemicool.com/elements/zinc.html.
Assuming the electron is in the lowest states and the atom is neutrally charged, it will fill an orbital before extending the next one. 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p H and He fill 1s as it holds two electrons. Li and Be fill 2s as it holds two electrons. B, C, N, O, F, and Ne will fill the 2p orbital as it holds 6 electrons (2p1, 2p2, and 2p3 orbitals). However, nitrogen will have one electron in each 2p1, 2p2, and 2p3 orbitals as an electron will not go two to an orbital until each orbital is filled. Neon completes the 2p orbital and is very stable (considered an inert gas--electrons are neither attracted nor want to leave the completed 2p orbital). Fluorine is the most electronegative element, as it wants to rip any electron it can to fill its 2p orbital. All noble gasses (right most on the periodic table) will complete a p-orbital. Periods 3-12 will fill a d-orbital. Lanthanoids and actinoids will fill the f-orbitals. So, for instance, Calcium (Ca) has an atomic number 20. You look up Ca on the periodic table. As it comes after He, it will have a 1p orbital filled. As it comes after Be, it will have a 2s orbital filled. As it comes after Ne, it will have a 2p orbital filled. And Ca will have a 3s orbital filled. Therefore, you note that Ca has electrons in the following orbitals: 1s, 2s, 2p, 3s. Another example is Fluorine (F), which would be: 1s, 2s, 2p1(2), 2p2(2), 2p3(1) where the parenthetical numbers note the number of electrons in each orbital.
Helium. It only has 2 electrons in its one orbital or energy level. The next biggest would be Neon.
The electron configuration for boron is 1s2 2s2 2p1, where the first two electrons fill the 1s orbital, the next two fill the 2s orbital, and the last electron occupies the 2p orbital. Boron has 5 total electrons.
Carbon is the sixth element with a total of 6 electrons. In writing the electron configuration for carbon the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for C goes in the 2s orbital. The remaining two electrons will go in the 2p orbital. Therefore the C electron configuration will be 1s2 2s2 2p2.
Atomic number of sodium is 11. So 11 electrons are there. First K shell could accomodate only 2. Now next L would have place for 8. So totally 10 electrons are firmy placed in the first two shells. Now remaining 1 electron would be in the third orbit M, that too in the s orbital. So sodium has 1 as valency. If suppose 8 electrons were there in the M shell, then s orbital 2, p orbital 6. But d orbital would be filled only after 4s orbital is filled with two electrons. So 8 electrons in s and p would make it less chemically reactive.
1s and 2s orbitals differ in that 2s orbitals lie farther away from the nucleus in the next principle energy level. Other than that, they occupy the same shape of orbital, spherical, as indicated by the s.
Neon has 10 electrons, so its orbital diagram would show two electrons in the 1s orbital, two in the 2s orbital, and six in the 2p orbital (with one electron in each of the three 2p orbitals). Each orbital can hold a maximum of 2 electrons with opposite spins.
The groundstate for Sodium (11-Na) is: 1S2 , 2S2, 2P6, 3S1 If you count the ^powers you notice it'll sum to 11, when Sodium is excited the outermost electron (3S1) will be excited from the 3S shell to the next shell up which is the 3P shell. The "core" electron configuration doesn't change so the first excited state is simply: 1S2 , 2S2, 2P6, 3P1 For the next excited state the electron that is now in the 3P shell will transition to the 4S shell before the 3D shell
Yes
ok so you'll notice that lithium is on the second row of the periodic table, this means that its the next orbital hydrogen = 1s1 orbital helium = 2s1 orbital lithium = 2s1, 1s2 orbital removing the outter electron from lithium means that lithium has lost a minus charge and therefore must have a plus charge, this is called a cation. removing the electron also means now that there are no electrons in the s2 level do lithium is left with a 2s1 orbital, this is a very stable configuration and lithium wont loose any more electrons so your lithium ion will be nucleus with 3 protons 4 neutrons and 2 electrons with a plus charge to represent the loss of an electron
The atom represented in the orbital diagram 1s2s2p is carbon (C). This notation indicates the electron configuration of carbon, where the 1s subshell is filled with 2 electrons, followed by 2 electrons in the 2s subshell and 2 electrons in the 2p subshell.
It would be the next Alkali Metal and would be placed under Francium.
In the case of excited phosphorus, the electron will bump up to the 3d level. This is the next closest location (in terms of energy) that the electron can go. Even though ground state phosphorus has no electrons in 3d, the atom can still access that sub-level because the principal quantum numbers for 3p (where its valence electrons are anyway) and 3d are the same.