polar
H2O is POLAR because its NDM is # from zero
H - Se (two dots on top and two dots on bottom) - H Se has two lone pairs (a total of four dots) and a Hydrogen is bonded to either side of it.
To draw the Lewis structure for selenium (Se) and two hydrogen (H) atoms, start by determining the total number of valence electrons: Se has 6 valence electrons, and each H has 1, giving a total of 8 valence electrons. Place the Se atom in the center and bond it to the two H atoms, using 2 electrons for each bond. After forming the two H-Se bonds, distribute the remaining 4 electrons around Se to satisfy its octet, typically showing two lone pairs. The final structure will have Se in the center with two H atoms bonded to it and two lone pairs on Se.
H-F bond is the most polar due to the high electronegativity difference between hydrogen and fluorine. Fluorine is the most electronegative element, causing the electrons in the bond to be strongly attracted towards the fluorine atom.
Polar!
2-naphthol has a polar molecule.
H - Se (two dots on top and two dots on bottom) - H Se has two lone pairs (a total of four dots) and a Hydrogen is bonded to either side of it.
yes. slightly polar
polar
To draw the Lewis structure for selenium (Se) and two hydrogen (H) atoms, start by determining the total number of valence electrons: Se has 6 valence electrons, and each H has 1, giving a total of 8 valence electrons. Place the Se atom in the center and bond it to the two H atoms, using 2 electrons for each bond. After forming the two H-Se bonds, distribute the remaining 4 electrons around Se to satisfy its octet, typically showing two lone pairs. The final structure will have Se in the center with two H atoms bonded to it and two lone pairs on Se.
polar
H-F bond is the most polar due to the high electronegativity difference between hydrogen and fluorine. Fluorine is the most electronegative element, causing the electrons in the bond to be strongly attracted towards the fluorine atom.
If you think to ammonia molecule, this is polar.
Polar!
SeCl4 would be non-polar covalent, because the electronegativity between Se and each Cl would be about the same. They differ by about 0.6. Don't multiply the the electronegativity by 4, because you want to find the difference between each Se---Cl bond. A polar molecule would have an electronegativity difference of less than 2. Electronegativity values are not something you memorize you always have to look them up
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The H-F bond is the most polar because fluorine is the most electronegative element among chlorine, bromine, and fluorine. The greater the electronegativity difference between the elements in a bond, the more polar the bond.
Yes. Sulfur (S) and hydrogen (H) will form a polar covalent bond.