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Why sulfuric acid is not used while reaction of alcohol with KI?

In the presence of sulphuric acid (H2SO4), KI produces HI Since is an oxidizing agent, it oxidizes HI (produced in the reaction to I2). As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used.


When Chlorine is bubbled in KI solution there is a color change because of?

When chlorine is bubbled in a potassium iodide (KI) solution, a color change occurs due to the oxidation of iodide ions (I⁻) to iodine (I₂). This process results in the formation of molecular iodine, which imparts a characteristic brown color to the solution. The reaction showcases the ability of chlorine, a strong oxidizing agent, to displace iodine from the iodide ion. The visual shift from colorless to brown indicates the presence of free iodine in the solution.


Why KI is added in redox iodometric titration even in the presence of sodium thiosulfate as a reducing agent?

In iodometric titrations sodium thiosulfate is the titrant whereas the KI will reduce the analyte; eg: Cu2+ to Cu+. The I2 produced is then titrated by the sodium thiosulphate. Cu2+ + I- --> CuI + I3- I3- + 2 S2O32- ¾® 3 I- + S4O62- To answer your question: KI (reducing agent) is added to generate the iodine by the reduction of the analyte (Cu2+) The formed iodine is then back-titrated with thiosulfate (titrant) to determine the amount of analyte originally present. As you can see the KI and sodium thiosulfate serve two different purposes. KI improves solubility of Iodine


Why KI is to be added to prepare to prepare iodine solution?

Potassium iodide (KI) is added to prepare iodine solution because it helps dissolve iodine (I2) in water, increasing its solubility and stability. This results in a more concentrated solution that is easier to work with for various applications, such as in titrations or as an antiseptic.


What is the name of the grey precipitate in the confirmatory test for mercury?

dimeric mercury ion Hg2+ 2 + 2 KI → Hg2I2 + 2 K+2 Hg2+ 2 + 2 NaOH → 2 Hg 2O + 2 Na+ + H2O Confirmation test for mercury:Hg2+ + 2 KI (in excess) → HgI2 + 2 K+HgI2 + 2 KI → K2[HgI4] (red precipitate dissolves)2 Hg2+ + SnCl2 → 2 Hg + SnCl4 (white precipitate turns gray)

Related Questions

Why sulfuric acid is not used while reaction of alcohol with KI?

In the presence of sulphuric acid (H2SO4), KI produces HI Since is an oxidizing agent, it oxidizes HI (produced in the reaction to I2). As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used.


What is the difference between iodometric titration and iodimetric titration?

Iodometric titration involves the titration of iodine with a reducing agent, while iodimetric titration involves the titration of iodide with an oxidizing agent. In iodometric titration, iodine is detected by a starch indicator to determine the end point, while in iodimetric titration, iodide ion concentration is determined by titration with a standard solution of an oxidizing agent.


Why you use KI solution in idiometric titration?

KI solution is commonly used in idiometric titrations because the presence of iodide ions allows for the detection of certain oxidizing agents through the formation of a characteristic color change with starch indicator. This method is particularly useful for determining the concentration of oxidizing agents such as chlorine or iodine in a sample solution.


What is the role of KI in the estimation of aniline?

ki is added to liberate iodine gas . this liberated iodine gas was then titrated with sodium thiosulphate to give a permanent white precipitate. this white precipitate indicates the endpoint of the titration..


Why add excess KI in iodometric titration?

Excess KI is added in iodometric titration to ensure that all the oxidizing agent (e.g., H2O2, Cl2) has reacted with the iodide ions (I-) present in the solution. This ensures complete reaction and accurate determination of the analyte concentration. The excess iodide ions also help prevent the oxidation of iodide to iodine by atmospheric oxygen, which can interfere with the titration.


What test is used to determine if excess hypochlorous acid is present in the oxidation mixture?

KI


When Chlorine is bubbled in KI solution there is a color change because of?

When chlorine is bubbled in a potassium iodide (KI) solution, a color change occurs due to the oxidation of iodide ions (I⁻) to iodine (I₂). This process results in the formation of molecular iodine, which imparts a characteristic brown color to the solution. The reaction showcases the ability of chlorine, a strong oxidizing agent, to displace iodine from the iodide ion. The visual shift from colorless to brown indicates the presence of free iodine in the solution.


What reagent is used to test for starch?

The reagent that is used to test for starch is a mixture of iodine and potassium iodide in water, or an Iodine - KI reagent. If the reagent turns blue-black in color, then starch is present.


What do ki ki mean in spanish?

"Ki ki" does not have a specific meaning in Spanish. It might be slang or a colloquial expression that varies depending on the context in which it is used.


What elements are found in iodized salt?

Iodized salt contain: - sodium chloride (NaCl) - iodine (as KI or KIO3) - an antikaking agent


What is the best spot test for Bi3 plus?

The best spot test for Bi³⁺ (bismuth ion) is the reaction with potassium iodide (KI). When bismuth ions are treated with KI, a yellow precipitate of bismuth iodide (BiI₃) is formed, which is a distinct and easily identifiable reaction. This test is sensitive and specific for bismuth, allowing for straightforward detection in various samples.


What can you make with iodine?

You could react : Potassium Metal with Iodine = K+I=KI = Potassium IodideSodium Metal with Iodine = Na+I=NaI = Sodium IodideLithium Metal with Iodine = Li+I=Lii = Lithium IodideFluoridesIodine fluoride: IFIodine trifluoride: IF3Iodine pentafluoride: IF5Iodine heptafluoride: IF7ChloridesIodine chloride: IClDiiodine hexachloride: [ICl3]2OxidesDiiodine pentaoxide: I2O5Diiodine tetraoxide: I2O4Tetraiodine nonaoxide: I4O9