Yes - very easily
-1.95V
In the reaction 2Na + Br₂ → 2NaBr, sodium (Na) is the element that is oxidized. Sodium loses one electron to form Na⁺ ions, resulting in an increase in its oxidation state from 0 to +1. Conversely, bromine (Br₂) is reduced as it gains electrons, decreasing its oxidation state from 0 to -1.
The iron is oxidized and the silver is reduced.
Mercury (Hg) is the most difficult to oxidize among the metals lead (Pb), mercury (Hg), sodium (Na), and calcium (Ca). Mercury has a unique electronic configuration that makes it reluctant to lose electrons and be oxidized.
The answer is not c.
In the reaction where Na is oxidized to Na+ in a chemical reaction, the oxidation state of Na changes from 0 to +1. This means that Na loses one electron and is oxidized.
sodium, Na is oxidized
Sodium (Na) is oxidized in the reaction to form sodium bromide (NaBr). In this reaction, sodium goes from an oxidation state of 0 to +1, indicating that it has lost an electron and been oxidized.
-1.95V
In this reaction, silver (Ag) has been oxidized. This is because silver changes from an oxidation state of 0 in Ag metal to an oxidation state of +1 in AgNO3. Oxidation involves the loss of electrons.
In this redox reaction, silver nitrate (AgNO3) is reacting with sodium (Na) to form sodium nitrate (NaNO3) and silver (Ag). The sodium is getting oxidized (losing electrons) while the silver in silver nitrate is getting reduced (gaining electrons).
It is a REDOX reaction. Sodium is oxidized by Fluorine which is itself reduced by the sodium. 2Na + F2 = 2NaF.
In this reaction, sodium is being oxidized. When sodium reacts with chlorine gas, sodium atoms lose electrons to form sodium ions, and this process involves the loss of electrons, which is characteristic of oxidation.
Oxidized.
Yes, sodium (Na) can be extracted from the electrolysis of its aqueous solution of sodium chloride (NaCl). During electrolysis, sodium ions are reduced at the cathode to form elemental sodium. Meanwhile, chloride ions are oxidized at the anode to produce chlorine gas.
The reduction potential of Na is -2.71 V and the reduction potential of Zn is -0.76 V. When Na is reduced, it gains electrons, so its reduction potential is written as a positive value (+2.71 V). When Zn is oxidized, it loses electrons, so its oxidation potential is -0.76 V. Therefore, the total reduction potential of the cell is +2.71 V - (-0.76 V) = +3.47 V.
Not sure what L(s) is supposed to be, but regardless, the oxidation state of Na changes from 1+ in NaOH to zero in Na(s).