Copper (II) Sulfate, is an ionic compound. If that is what you are asking.
Anytime you have a metal that has a number in parenthesis after it, you're going to be using ions. The number in paranthesis is what indicates the charge on the ion. For example, Copper (II) would have a charge of +2.
Aqueous copper sulfate solution contains free ions (Cu2+ and SO4 2-) that can carry electrical charge and allow the solution to conduct electricity. In contrast, solid copper sulfate does not contain free ions and is unable to conduct electricity because the ions are locked in a fixed position within the solid lattice.
The chemical equation is:Ba+ + 2 Cl- + 2 Na+ + SO4- = BaSO4(s) + 2 Cl- + 2 Na+
A physical change is different from a chemical change in two ways:1) In a physical change no new substances are made; in a chemical change new substances are made.2) A physical change can be easily reversed; a chemical change cannot be easily reversed.Dissolving copper sulphate in water does not produce a new substance. The copper sulphate solution is a mixture, not a pure substance.Also, by evaporating the water you can easily get the copper sulphate back again.So, dissolving copper sulphate is a physical change.Sometimes, though, when water is added to copper sulphate, it reacts with the water to form copper sulphate pentahydrate, which is a new compound. This would be a chemical change, but actually dissolving it is indeed a physical change only.See these sites for more information:http://www.bbc.co.uk/schools/ks3bitesize/science/chemistry/chem_react_2.shtmlhttp://www.chem4kids.com/files/matter_chemphys.html
No. This is a redox question. It is asking whether the reaction will occur spontaneously. In order for Mg+2 to spontaneously oxidize Cu(s), Mg+2 needs to have a higher reduction potential (the tendency to be reduced) than Cu+2. Check a redox table to see: Mg2+ + 2 e− --> Mg(s) E° = −2.372 Cu2+ + 2 e− --> Cu(s) E° = +0.340 (More favorable reaction) Cu2+ has a higher reduction potential, meaning Mg2+ will not oxidize Cu(s).
In this case, zinc will undergo oxidation and copper ions will experience reduction. The reduction half-reaction is Cu^2+ (aq) + 2e^- → Cu (s), and the oxidation half-reaction is Zn (s) → Zn^2+ (aq) + 2e^-. Overall, the reaction is Zn (s) + Cu^2+ (aq) → Zn^2+ (aq) + Cu (s).
The bond in copper(II) sulfate is primarily ionic, between the copper ion (Cu2+) and the sulfate ion (SO4 2-). This means that copper(II) sulfate is an ionic compound, where the copper ion is attracted to the sulfate ion through opposite charges.
Copper sulfate is an ionic compound. It forms when copper ions (Cu2+) bond with sulfate ions (SO4^2-) through ionic bonds, where electrons are transferred from one atom to another. This results in the formation of a positively charged copper ion and a negatively charged sulfate ion.
The valency of copper in copper sulfate (CuSO4) is +2. This means that copper has a charge of +2 in this compound and it forms ionic bonds with the sulfate ion.
When copper sulfate and sodium hydroxide are mixed, a blue precipitate of copper hydroxide is formed. This is because the hydroxide ions from sodium hydroxide react with the copper ions from copper sulfate to form the insoluble copper hydroxide. The net ionic equation for this reaction is Cu^2+ (aq) + 2OH^- (aq) → Cu(OH)2 (s).
copper+sulphur+oxygen then theres an arrow, but i don't know how 2 do an arrow copper sulphate
Yes, copper sulphate can dissolve in water. When added to water, copper sulphate dissociates into copper ions (Cu2+) and sulphate ions (SO4 2-), forming a blue-colored solution.
In copper sulfate (CuSO4), the bonds present are ionic bonds between the positively charged copper ion (Cu2+) and the negatively charged sulfate ion (SO4 2-). These ionic bonds form due to the transfer of electrons from the copper atom to the sulfate group, resulting in the attraction between the oppositely charged ions.
Copper sulfate is a polar compound because of its ionic nature. It contains copper ions (Cu2+) and sulfate ions (SO4 2-) which have opposite charges and are attracted to each other, resulting in a polar molecule.
The name of the compound with the formula Cu2SO4 is Copper I sulphate or Cuprous sulphate.
The ionic equation for the reduction of copper sulfate (CuSO4) to copper oxide is: Cu^2+ + 2e^- → Cu This equation represents the reduction half-reaction where copper ions (Cu^2+) gain two electrons to form solid copper (Cu). The formation of copper oxide involves further reactions and would require a more comprehensive equation.
the answer is..... 2
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