Yes, by measuring both the stars orbital period and its change in velocity over the orbit.
Yes, it is possible for a body's velocity and acceleration to be in opposite directions. This would result in the body's velocity decreasing over time while its acceleration remains negative. On a velocity-time graph, this situation would be represented by a curve that starts with a positive velocity and decreases over time.
No, average velocity is the total displacement divided by the total time taken. The slope of the tangent to the curve on a velocity-time graph at a specific instant of time gives the instantaneous velocity at that moment, not the average velocity.
Velocity is the slope of the position vs. time curve.
No, it is not. At a constant speed, yes. But velocity has a direction component, and by running on (following) a curve, a change of direction (and, therefore, velocity) will have to be made. Again, note that speed can stay the same, but velocity has a direction vector associated with it that cannot be ignored.
The slope of the tangent line in a position vs. time graph is the velocity of an object. Velocity is the rate of change of position, and on a graph, slope is the rate of change of the function. We can use the slope to determine the velocity at any point on the graph. This works best with calculus. Take the derivative of the position function with respect to time. You can then plug in any value for x, and get the velocity of the object.
To determine velocity from an acceleration-time graph, you can find the area under the curve of the graph. This area represents the change in velocity over time. By calculating this area, you can determine the velocity at any given point on the graph.
To determine an object's position from a velocity graph, you can find the area under the velocity curve. The area represents the displacement or change in position of the object. The position at any given time can be calculated by adding up the areas under the curve up to that time.
To determine the position of an object from a velocity graph, you can find the area under the velocity curve. The area represents the displacement of the object. The position can be calculated by integrating the velocity function over a specific time interval.
To find the position from a velocity-vs-time graph, you need to calculate the area under the velocity curve. If the velocity is constant, the position can be found by multiplying the velocity by the time. If the velocity is changing, you need to calculate the area under the curve using calculus to determine the position.
No, the velocity of a car is not constant when it is going around a curve. The direction of the car's velocity is changing as it navigates the curve, even if its speed remains the same, so the velocity is not constant.
The graph of velocity-time is the acceleration.
Since the outside curve has a higher velocity, it has more erosion meaning the inside curve has a slower velocity more deposition causing it to be shallower. The outside curve is deep.
if its a velocity / time curve, it will show diminishing acceleration (slope of the curve) up to terminal velocity (forces balanced)
An object can maintain a constant velocity in a curve if it experiences a centripetal force directed towards the center of the curve, balancing its inertia. This occurs in circular motion when the object's speed and direction of motion are not changing, even though its velocity vector (including direction) is changing.
Yes, it is possible for a body's velocity and acceleration to be in opposite directions. This would result in the body's velocity decreasing over time while its acceleration remains negative. On a velocity-time graph, this situation would be represented by a curve that starts with a positive velocity and decreases over time.
No, average velocity is the total displacement divided by the total time taken. The slope of the tangent to the curve on a velocity-time graph at a specific instant of time gives the instantaneous velocity at that moment, not the average velocity.
There is no such thing as a "slope under the curve", so I assume that you mean "slope of the curve". If the curve is d vs. t, where d is displacement and t is time, then the slope at any given point will yield (reveal) the velocity, since velocity is defined as the rate of change of distance with respect to time. Mathematically speaking, velocity is the first derivative of position with respect to time. The second derivative - change in velocity with respect to time - is acceleration.