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Is the event horizon the distance from the singularity at which the acceleration due to gravity exceeds the speed of light?
Not exactly ... notice that it doesn't make sense to say that
an acceleration is equal to a speed.
The event horizon is the distance at which the escape velocity
is equal to the speed of light.
That's the square root of [ 2 (gravitational constant) (central mass)/(distance from its center) ] ===========================
I never played much with this before. But you asked, and I did, and
I thought you might be interested in a couple of tidbits that fell out:
The next logical step is to set the escape velocity equal to 'c', and then
massage things around and solve for the distance:
2 G M / D = c2
D = 2 G M / c2 We know 'G' and 'c' , so then the distance to the event horizon is
D = (2 x 6.67 x 10-11) M / (3 x 108)2 D = 1.482 x 10-27 M And voyla ! There you have it ... the distance in terms of the mass.
-- For 1 Earth mass, the radius to the event horizon is 8.86 millimeters.
-- For 1 solar mass, it's 2.95 kilometers
-- For 1 million solar masses, it's 2.95 million kilometers, about 7.6 times
the radius of the Moon's orbit, and about 4.2 times the sun's radius.
This helps clarify what's going on with black holes. It's not that they have such
crazy gravity, nor can they reach out and grab you and suck you in as you pass
by. It's just that you can't get CLOSE ENOUGH to the center of mass of any
other kind of body to be in the region of the extreme gravity of an event
horizon.
What else can I help you with?
Why is acceleration due to gravity zero at the centre of the Earth?
Acceleration due to the earth's gravity is zero at the center of the Earth because at that point the mass of the earth is equally distributed in all directions, so pulling equally in all directions for a net zero pull. Simplistically, acceleration due to gravity decreases as distance from the center decreases. At the center the distance is zero, hence gravity is zero.
What happen to matter when it enters a black hole?
It is first stretched then pressurised. so if a human was to enter a black hole, you would first be turned into a spaghetti-looking thing then you will be pressureised. too much pressure on any human will make them explode.
What is the acceleration of gravity on the surface of Venus?
88% of what it is here ; so 28.2 feet /sec 2
If black holes have infinite gravity why don't they affect our solar system?
To say that black holes have infinite gravity is somewhat misleading. Theoretically, the strength of gravity at the singularity is infinite, but it diminishes with distance. While technically there is some gravitational attraction, even across light years of space, the effect is tiny at such distances.
What is the acceleration for the pull of gravity?
If you mean acceleration due to gravity it is ~9.8m/s2
What are the Factors influencing acceleration due to gravity?
The factors influencing acceleration due to gravity are the mass of the object and the distance from the center of the Earth. Objects with more mass experience a stronger gravitational force, which leads to a higher acceleration due to gravity. Additionally, the acceleration due to gravity decreases as the distance between the object and the center of the Earth increases.
Is the acceleration cause by the gravity constant?
acceleration caused by gravity is not the same because it varies from the mass and the distance betwwen the two objects
How do you calculate the acceleration of gravity?
The acceleration of gravity can be calculated using the formula a = 9.81 m/s^2, where "a" represents the acceleration due to gravity. This value is a constant for objects falling in Earth's gravitational field.
What is the value of acceleration due to gravity in space?
The magnitude of acceleration due to gravity depends on the mass of the object toward which you're attracted by gravity, and on your distance from it. There are trillions of different possibilities in space.
Why is acceleration due to gravity low in space?
The acceleration due to gravity from any given object decreases with distance from it. Specifically, gravity scales with the inverse of the square of the distance. That means, for example, if you double your distance, gravitational acceleration is reduced to a quarter of what it was. Most areas of space are quite empty, far from any massive objects, which means that acceleration due to gravity will be quite small. Conversely, some areas of space that are very near massive objects can have enormous gravitational acceleration.
Are acceleration due to gravity on small stone and big stone equal?
Yes, the acceleration due to gravity on both small and big stones is equal because it depends only on the mass of the Earth and the distance from its center. The mass of the stone does not affect the acceleration due to gravity.
How does the Acceleration of gravity vary with the distance from center of earth?
It looks to me likeAcceleration of gravity = G M / R2The 'M' contributing to the acceleration is the 'M' inside the 'R' of interest. If the earth is homogeneous,then the 'M' is proportional to the volume inside the 'R', which varies as R3 .So the acceleration is proportional to [ M / R2 ], in turn proportional to [ R3 / R2 ] = R.Again, that's assuming the earth is homogeneous, which we know it isn't. But for a uniform,homogeneous 'planet', the acceleration of gravity varies directly with the distance from the center.
What is the dimensional formula of acceleration due to gravity?
An acceleration is a velocity divided by a time, so you have: acceleration = velocity / time acceleration = (distance / time) / time acceleration = distance / time2 The gravitational field can also be expressed as force / mass; this is equivalent to distance / time2.
What is the formula for work done against gravity?
Work Done = Force x Distance = Power / Time = (Force x speed)/Time
How does the acceleration of gravity depend on it's distance from the center of the Earth?
acceleration due to gravity is given by, g=GM/R2 Hence distance from the earth increases g decreases and viceversa. So g at poles is greater than g at equator.
What happens to the acceleration due to gravity as you move farther away from the center of the earth?
The acceleration due to gravity decreases as you move farther away from the center of the Earth. This is because gravity weakens with distance according to the inverse-square law.
How does acceleration due to gravity changes with altitude?
The acceleration of gravity ... on or near the Earth, for example ... is inversely proportional to the square of the distance from the center of the Earth. So it diminishes as you rise from the surface. When you have ascended to an altitude of one Earth radius ... about 4,000 miles ... your distance from the center is then two Earth radii, so the acceleration of gravity has shrunk to 1/4 of its value on the surface.
