Tin on its own is a neutral atom but will form cations since it is a metal.
The anion in SnBr4 is bromide (Br⁻). In this compound, tin (Sn) has a +4 oxidation state, and each bromine atom contributes a -1 charge, resulting in a total of four bromide anions to balance the charge of the tin cation. Therefore, SnBr4 consists of one tin cation and four bromide anions.
anion
Formula: TiN, not to be confused with Tin(Stannum)
Anion is a negative ion (Cl-) and cation is a positive ion (Na+).
AgNO3 consists of the cation Ag+ and the anion NO3-. Ag+ is the silver cation, while NO3- is the nitrate anion.
Tin itself is a neutral element and therefore neither a cation nor an anion. A single tin atom can form a cation by donating two or four of its electrons to more electronegative atoms. A single tin atom is not electronegative enough to form an anion, but together with oxygen atoms, a tin atom can form a polyatomic anion.
The cation would be C6H5NH3+ and the anion would be C6H5NH-
The cation of potassium cyanide is potassium (K+) and the anion is cyanide (CN-).
Anion
anion
Formula: TiN, not to be confused with Tin(Stannum)
Can an ionic compound ever consist of a cation-cation or anion- anion bond? Explain.
Oxygen is neither a cation nor an anion. It is a neutral element.
When lead (IV) sulfate reacts with tin (II) chlorate, the lead (IV) cation (Pb^4+) will combine with the chlorate anion (ClO3^-) to form lead (IV) chlorate, Pb(ClO3)4. The tin (II) cation (Sn^2+) will combine with the sulfate anion (SO4^2-) to form tin (II) sulfate, SnSO4.
CR is a cation.
Tin(IV) oxide is primarily considered an ionic compound, as it is composed of a metal cation (tin) and a non-metal anion (oxygen) that form an ionic bond.
Anion is a negative ion (Cl-) and cation is a positive ion (Na+).